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mote1985 [20]
3 years ago
13

What is the product of 0.6 and 7

Mathematics
2 answers:
Lunna [17]3 years ago
8 0
Product means multiplication.

0.6 * 7 = 4.2
yuradex [85]3 years ago
3 0
0,6·7=6/10·7=42/10=4,2

<em>Answer: 4,2</em>
You might be interested in
There were five teams entered in a competition. Each team consisted of either only boys or only girls. The number of team member
WINSTONCH [101]

Answer:

21.

Step-by-step explanation:

Since there were five teams entered in a competition, and each team consisted of either only boys or only girls, with the number of team members being 9, 15, 17, 19 and 21 members, if after one team of girls had been knocked out of the competition, the number of girls still competing was three times the number of boys, to determine how many girls were in the team that was eliminated, the following calculation must be performed:

9 + 15 + 17 + 19 = 60/4 = 15

9 + 15 + 17 + 21 = 62/4 = 15.5

9 + 15 + 19 + 21 = 64/4 = 16

9 + 17 + 19 + 21 = 66/4 = 16.5

15 + 17 + 19 + 21 = 72/4 = 18

Thus, since 15 x 3 equals 45, and 45 plus 15 equals 60, the number of girls on the team that was eliminated was 21.

3 0
3 years ago
122 x 69, please help I’m
slava [35]

8418 just put it in a calculator next time

4 0
3 years ago
Help help help help!!!!!
Art [367]
Area is equal to length times width, so we can use this over here:

Area = lw
Area = (x+7)(x+1)
Area = x^2+x+7x+7
Area = x^2+8x+7

Hope this helps!! :)
3 0
3 years ago
Read 2 more answers
Modeling Radioactive Decay In Exercise, complete the table for each radioactive isotope.
Travka [436]

Answer :

The amount after 1000 years will be, 5.19 grams.

The amount after 10000 years will be, 0.105 grams.

Step-by-step explanation :

Half-life = 1599 years

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{1599\text{ years}}

k=4.33\times 10^{-4}\text{ years}^{-1}

Now we have to calculate the amount after 1000 years.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 4.33\times 10^{-4}\text{ years}^{-1}

t = time passed by the sample  = 1000 years

a = initial amount of the reactant  = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

1000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}

a-x=5.19g

Thus, the amount after 1000 years will be, 5.19 grams.

Now we have to calculate the amount after 10000 years.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 4.33\times 10^{-4}\text{ years}^{-1}

t = time passed by the sample  = 10000 years

a = initial amount of the reactant  = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

10000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}

a-x=0.105g

Thus, the amount after 10000 years will be, 0.105 grams.

4 0
3 years ago
=500+176 <br><br> what is the answer
natima [27]

Answer:

676

Step-by-step explanation:

you just add them

6 0
3 years ago
Read 2 more answers
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