Answer:
Step-by-step explanation:
the answer is unknown because there is no answer to that question and if there was it would be odd an would not make sence so that is a true of false question
Answer:
(b) 
General Formulas and Concepts:
<u>Calculus</u>
Differentiation
- Derivatives
- Derivative Notation
Integration
Integration Method: U-Substitution and U-Solve
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify given.</em>
<em />
<u>Step 2: Integrate Pt. 1</u>
<em>Identify variables for u-substitution.</em>
- Set <em>u</em>:

- [<em>u</em>] Apply Trigonometric Differentiation:

- [<em>du</em>] Rewrite [U-Solve]:

<u>Step 3: Integrate Pt. 2</u>
- [Integral] Apply Integration Method [U-Solve]:

- [Integrand] Simplify:

- [Integral] Apply Arctrigonemtric Integration:

- Simplify:

- [<em>u</em>] Back-substitute:

∴ we used substitution to <em>find</em> the indefinite integral.
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Learn more about integration: brainly.com/question/27746468
Learn more about Calculus: brainly.com/question/27746481
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Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Integration
Answer:
30
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
A because the line perpendicular to this line would have the reciprocal slope!
Hope this helps!
Given:
The dimensions of a rectangular plot are 50 yards by 41 yards.
To find:
The area of the plot.
Solution:
We know that, the area of a rectangle is

So, the area of the rectangular plot is:


Therefore, the area of the rectangular plot is 2050 square yards.