This is a combination problem.
Given:
12 students
3 groups consisting of 4 students.
Mark can't be in the first group.
The combination formula that I used is: n! / r!(n-r)!
where: n = number of choices ; r = number of people to be chosen.
This is the formula I used because the order is not important and repetition is not allowed.
Since Mark can't be considered in the first group, the value of n would be 11 instead of 12. value of r is 4.
numerator: n! = 11! = 39,916,800
denominator: r!(n-r)! = 4!(11-4)! = 4!*7! = 120,960
Combination = 39,916,800 / 120,960 = 330
There are 330 ways that the instructor can choose 4 students for the first group
The answer for the circumference is 43.96 and the area is 153.86
0.24 should be your answer
Jacob counts 48 ants all together 37 + 11 = 48
9514 1404 393
Answer:
(x, y) = (-11, 4)
Step-by-step explanation:
You can subtract 3 times the second equation from the first to eliminate y.
(7x +9y) -3(x +3y) = (-41) -3(1)
4x = -44
x = -11
Substituting into the second equation gives ...
-11 +3y = 1
3y = 12
y = 4
The solution is (x, y) = (-11, 4).
