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Rina8888 [55]
4 years ago
11

In hodags (mythical creatures of wisconsin), brown fur (b) is dominant over gray fur (b) and long horns (h) are dominant over sh

ort horns (h). two true-breeding hodags, one with brown fur and long horns and the other with gray fur and short horns mate and produce an f1. two f1 individuals are mated. what proportion of the offspring will exhibit a phenotypic combination that is different from the p generation? assume the genes for fur color and horn length are on different chromosomes.
Biology
1 answer:
mezya [45]4 years ago
5 0
Well I think I might know this since I was born and grew up in WI, but don't be 100% dependent with my answer because I'm only in 7th grade and I am doing high school stuff. Well my guess is the proportion of the genes is 1/2 because when a offspring is produced the genes are split from each parent rather its a human baby, a mammal, a fish, a reptile, a insect, or a  plant. Although, I don't know what f1 means except for it being a control on the computer lol. But like I said I'm only in 7th grade so I don't know everything but I'm smarter than a average 7th grader.

                 Hope this helps! (it probably wont though)




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Since pink bodies are from a dominant gene and yellow are from a recessive gene, the change of them having pink child is 75%, and a yellow child is 25%. Pink bodies are classified with an uppercase letter “P” and a lowercase “p”, making is heterozygous. It’s dominant, but still carries the possibility for the recessive gene to come through. As long as the genotype is classified with at least one uppercase letter, it’s automatically a dominant gene. After following the Punnett square, you’ll find:

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Each square (there’s 4) is worth 25% (so when added up, it totals to be 100%).
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