Answer:
Problem B: x = 12; m<EFG = 48
Problem C: m<G = 60; m<J = 120
Step-by-step explanation:
Problem B.
Angles EFG and IFH are vertical angles, so they are congruent.
m<EFG = m<IFH
4x = 48
x = 12
m<EFG = m<IFH = 48
Problem C.
One angle is marked a right angle, so its measure is 90 deg.
The next angle counterclockwise is marked 30 deg.
Add these two measures together, and you get 120 deg.
<J is vertical with the angle whose measure is 120 deg, so m<J = 120 deg.
Angles G and J from a linear pair, so they are supplementary, and the sum of their measures is 180 deg.
m<G = 180 - 120 = 60
Answer:
28.26
Step-by-step explanation:
A=3.14 r^2
3.14x3x3
3.14x9
28.26
Hope this helps! :)
(Please don't hate on me if its wrong)
Answer:
51
Step-by-step explanation:
big windows 48
small windows 12
broken windnows9
unbroken windows= 48+12-9= 51
unbroken 51 windows