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2 years ago

if i were to plug this in my ps4 usb port and connect it to the tv would it work please and if so please explain

Computers and Technology

2 answers:

denis-greek [22]2 years ago

5 0

There’s no point of buying that and wasting more money. You could just buy a HDMI port and plug it in right away from the HDMI in port on the play station to your HDMI out port on the tv.

Brilliant_brown [7]2 years ago

4 0

Probably, most likely yes. this is just basically adding a bit of extra length. the ps4 port goes in the end and the part for the tv acts as a hdmi cord.

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Answer:

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Integers and booleans. Write a program RightTriangle that takes three int command-line arguments and determines whether they con

icang [17]

Answer:

The programming language is not stated;

I'll answer using C++

#include<iostream>

#include<cmath>

using namespace std;

int main()

{

int side1, side2, side3;

cout<<"Enter the three sides of the triangle: "<<endl;

cin>>side1>>side2>>side3;

if(side1<=0 || side2 <= 0 || side3 <= 0) {

cout<<"Invalid Inputs";

}

else {

if(abs(pow(side1,2) - (pow(side2,2) + pow(side3, 2)))<0.001) {

cout<<"Right Angled";

}

else if(abs(pow(side2,2) - (pow(side1,2) + pow(side3, 2)))<0.001) {

cout<<"Right Angled";

}

else if(abs(pow(side3,2) - (pow(side2,2) + pow(side1, 2)))<0.001) {

cout<<"Right Angled";

}

else {

cout<<"Not Right Angled";

}

return 0;

}

Explanation:

The following line declares the three variables

int side1, side2, side3;

The next line prompts user for input of the three sides

cout<<"Enter the three sides of the triangle: "<<endl;

The next line gets user input

cin>>side1>>side2>>side3;

The following if condition checks if any of user input is negative or 0

if(side1<=0 || side2 <= 0 || side3 <= 0) {

cout<<"Invalid Inputs";

}

If otherwise

else {

The following if condition assumes that side1 is the largest and test using Pythagoras Theorem

if(abs(pow(side1,2) - (pow(side2,2) + pow(side3, 2)))<0.001) {

cout<<"Right Angled";

}

The following if condition assumes that side2 is the largest and test using Pythagoras Theorem

else if(abs(pow(side2,2) - (pow(side1,2) + pow(side3, 2)))<0.001) {

cout<<"Right Angled";

}

The following if condition assumes that side3 is the largest and test using Pythagoras Theorem

else if(abs(pow(side3,2) - (pow(side2,2) + pow(side1, 2)))<0.001) {

cout<<"Right Angled";

}

If none of the above conditions is true, then the triangle is not a right angles triangle

else {

cout<<"Not Right Angled";

}

}

return 0;

Download cpp

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3 years ago