Answer: 86
Step-by-step explanation:
is in quadrant I, so
.
is in quadrant II, so
.
Recall that for any angle
,

Then with the conditions determined above, we get

and

Now recall the compound angle formulas:




as well as the definition of tangent:

Then
1. 
2. 
3. 
4. 
5. 
6. 
7. A bit more work required here. Recall the half-angle identities:



Because
is in quadrant II, we know that
is in quadrant I. Specifically, we know
, so
. In this quadrant, we have
, so

8. 
Answer:
Step-by-step explanation:
m=1, (10,5)
y=mx+b
5=1(10)+b
5=10+b
b=-5
y=x-5
A "roster" here is essentially a version of the set with all of elements listed out. Here, those elements are all of the odd numbers between 20 and 30, so our list would be
{21, 23, 25, 27, 29}
Answer:
149
Step-by-step explanation: