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DiKsa [7]
3 years ago
9

The acceleration function a(t) (in m/s2) and the initial velocity v(0) are given for a particle moving along a line.

Mathematics
1 answer:
klemol [59]3 years ago
7 0

Answer:

A: v(t)=-t^2+4t-5

Step-by-step explanation:

Acceleration is second derivative of position, velocity is first derivative. Therefore, the velocity is the integral of acceleration.

v(t)=\int\ {2t+4} \, dt

Integrate:

-t^2+4t+C

V(0)=-5:

-0^2+4(0)+C=-5\\C=-5

Therefore, v(t):

v(t)=-t^2+4t-5

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