Answer:
no real solutions
Step-by-step explanation:
Given a quadratic equation in standard form
ax² + bx + c = 0 : a ≠ 0
Then the nature of the roots can be determined from the discriminant
b² - 4ac
• If b² - 4ac > 0 then 2 real and distinct roots
• If b² - 4ac = 0 then 2 real and equal roots
• If b² - 4ac < 0 then no real roots
Given
n(7n + 8) = - 10 ← distribute left side
7n² + 8n = - 10 ( add 10 to both sides )
7n² + 8n + 10 = 0 ← in standard form
with a = 7, b = 8 and c = 10, thus
b² - 4ac = 8² - (4 × 7 × 10) = 64 - 280 = - 216
Since b² - 4ac < 0 the equation has no real roots
