2(x-1)+4x=3(x-1)+7 I need to solve to see if it solves, has no solution, or infinitely many solutions.

In conditional probability, the notation P(A | B) is read:

il63 [147K]

The probability of a student taking the bus given that the student is a sophomore is 0.83

The complete question is attached with the answer below:-

<h3 /><h3>What is probability?</h3>

Probability is defined as the ratio of the number of favorable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.

Given that:

P(Walk to school | Sophomore) = 3 /(2 + 25 + 3) = 0.1
To calculate the probability of a student taking the bus given that the student is a sophomore, we make use of:
P(Take the bus | Sophomore ) = 25/(2 + 25 + 3)

Rewrite properly as:

$P_r = \dfrac{25}{3+2+25}$

So, we have:

$P_r = \dfrac{25}{30}$

Divide 25 by 30

Pr = 0.83

Hence, the probability of a student taking the bus given that the student is a sophomore is 0.83

To know more about probability follow

brainly.com/question/24756209

#SPJ1

6 0

2 years ago

432 square feet 2/3 is with what's the length

Radda [10]

432 divide by 3. then multiply by two equals 288.

3 0

3 years ago

What does 1/3+1/6 equal

77julia77 [94]

1/3+1/6

(2*1)/6+1/6

2/6+1/6

3/6
<span>

1/2</span>

4 0

4 years ago

Read 2 more answers

Determine whether the following pair of lines is parallel, perpendicular or neither 2x+3y=3: 2y=3x-4

QveST [7]

First, you have to simplfy your equations, 2x+3y=3. Subtract 2x from both sides, get 3y=-2x+3. Divide each side by 3, get y=-2/3x+1.
Simplify your other equation, 2y=3x-4. Divide each side by 2, get y=3/2x-2.
Now you have your 2 equations, y=-2/3x+1, and y=3/2x-2. These lines are perpendicular if you make a graph and plot the lines.

8 0

3 years ago

A line passes through (9,-9) and (10,-5).

Sedaia [141]

$\bf (\stackrel{x_1}{9}~,~\stackrel{y_1}{-9})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{-5}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-5-(-9)}{10-9}\implies \cfrac{-5+9}{1}\implies 4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-9)=4(x-9)\implies y+9=4(x-9) \\\\\\ y+9=4x-36\implies y=4x-45\implies \stackrel{\textit{standard form}}{-4x+y=-45}$

just a quick note

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

now, however the inappropriate choices here, do have it with a negative "x".

6 0

4 years ago

Read 2 more answers