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amid [387]
4 years ago
10

What is happening to this graph when the x-values are between -8 and -4?

Mathematics
1 answer:
NikAS [45]4 years ago
6 0
Answer: C. It’s increasing

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adoni [48]
A: 1
B: 2
C: 4
D: 5
Total = 1 + 2 + 4 + 5 = 12

C:total = 4/12 = 1/3

A full circle has 360 deg.

1/3 * 360 deg = 120 deg.
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3 years ago
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Neko [114]
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Round 5.785 to the nearest hundreth
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3 years ago
Use the equation below to identify the value fo each variable for the circle.
natita [175]

Answer:

The equation of the circle in standard form is: (x - 2)² + (y - 4)² = 9

Step-by-step explanation:

* Lets revise the standard form of the equation of the circle

- If the center of the circle is point (h , v) and the radius of the

 circle is r, then the standard form of the equation of the circle

 is (x - h)² + (y - v)² = r²

- (x , y) a general point on the circle

* Lets look to the picture

- The center of the circle is point (2 , 4)

- The highest point on the circle is (2 , 7) and the lowest point

 on the circle is (2 , 1)

∴ The diameter of the circle = 7 - 1 = 6

∵ The radius = 1/2 the diameter

∴ The radius of the circle = 1/2 × 6 = 3

* Now we can write the equation of the circle

∵ h = 2 and v = 4

∵ r = 3

∴ (x - 2)² + (y - 4)² = 3²

∴ The equation of the circle in standard form is:

   (x - 2)² + (y - 4)² = 9

7 0
3 years ago
Find the relative extrema, if any, of the function. Use the Second Derivative Test if applicable. (If an answer does not exist,
belka [17]

Answer:

We have the function g(x) = x^3 -15*x

First, to find extrema, we can find the zeros of the first derivative.

g'(x) = 3*x^2 -15

g'(x) = 0 = 3*x^2 - 15

x^2 = 15/3 = 5

x = √5

x = -√5

Now, watching at the second derivative we have:

g''(x) = 6*x

so when we have

g''(√5) = 6*√5 > 0 then x = √5 is a local minimum

g''(-√5) = -6*√5 < 0, then x = -√5 is a local maximum.

3 0
3 years ago
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