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Ratling [72]
3 years ago
11

A sphere and a cylinder have the same radius and height. The volume of the cylinder have the same height and radius. The volume

of the cylinder is 27pi ft. What equation gives the volume of the sphere ?
Mathematics
1 answer:
USPshnik [31]3 years ago
6 0

Step-by-step explanation:

radius of sphere, rs

radius of cylinder, rc

height of cylinder, h

given: h = rs = rc =r..eq1

volume of cylinder, vc = 27pi ft...eq2

volume of cylinder, vc = pi × rc^2 × h...eq3

volume of sphere, vs = 4/3(pi×rs^3)...eq4

subst for h & rs from eqn 1 in eqn 3...

vc = pi x r^2 x r= pi x r^3...eqn 5

subst for vc from eqn 2 in eqn 5...

=> 27 pi ft = pi x r^3

=> 27 = r^3

=> r = 3ft...eqn 6

subst for rs from eqn 1 in eqn 4

vs = 4/3 (pi x r^3)...eqn7

subst for pi x r^3 from eqn 5 in eqn 7

vs = 4/3 vc = 4/3 (27pi ft) = 36 pi ft

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3 years ago
What two partial products would you add to find 513 x 46
Afina-wow [57]
First, let me do the Mathematical part of that, and then I shall explain the theory behind it.

Mathematical part:
We are going to multiply 513 with 46. So the two partial products that we are going to choose are 40 and 6.

Multiply 513 with 6 first.

    513
    x46
--------------------------
      18 (as 6*3 = 18)
      60 (as 6*10 = 60; In 513, the digit at tenths place is 1, so 1*10=10)
  3000 (as 6*500 = 3000; In 513, 5 is at hundredth place, so 5*100=500)
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    400 (as 40*10 = 400)
20000 (as 40*500 = 20000)
--------------------------
23598 (Add all of them)


Theory:
As you can see above that we have chosen the two partial products individually which are 6 and 40. Since 4 in 46 is in tenth place, we have to consider it 40 (since 4*10 = 40). One by one, we first multiply 6 with 513. Then we move to the tenth place, and multiply 513 with 40. At the end, we have added all the results we found after multiplication.

Check: If we check the multiplication result by using the calculator, we would get the same result (23598).

Another Method (instant):
513 * (40+6) = (513*40) + (513*6) = 23598.
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