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vampirchik [111]
4 years ago
6

Simplify 5-(-1) Quickly answer pls

Mathematics
2 answers:
erik [133]4 years ago
5 0

Answer:

5-(-1)

5+1

6

Step-by-step explanation:

Tju [1.3M]4 years ago
5 0

Answer:

6

Step-by-step explanation:

5-(-1)

5+1

= 6

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A and B contributed 2700 and 1800 respectively to start a business. They agreed to share the profit in the ratio 7:5 respectivel
Phoenix [80]

Answer:

58.33%

Step-by-step explanation:

A's Contribution = 2700

B's Contribution= 1800

Ratio = 7:5

Profit = 900

Total Ratio = 7+5 = 12

First , Calculate both share of the profit.

A's Share= 7/12 ×900

525

B's share= 5/12 ×900

375

Now , express A's Share as a percentage

A's Share= 525/900 ×100

58.33%

5 0
3 years ago
Select all the correct answers.
Schach [20]

Answer:

....................

Step-by-step explanation:

5 0
3 years ago
Roes bushes cost $5 and tomato plant cost $2. Write an expression that represent the show the total cost for any number of rose
Anna [14]

<em><u>Expression that represent the show the total cost for any number of rose bushes and tomato plant is:</u></em>

Total\ cost = 5x + 2y

<em><u>Solution:</u></em>

Let "x" be the number of roses bush

Let "y" be the number of tomato plant

Cost of 1 rose bush = $ 5

Cost of 1 tomato plant = $ 2

To find: Expression that represent the show the total cost for any number of rose bushes and tomato plant

Total cost = number of roses bush x Cost of 1 rose bush + number of tomato plant x Cost of 1 tomato plant

Total\ cost = x \times 5 + y \times 2\\\\Total\ cost = 5x + 2y

Thus the expression is found where, x and y are the number of rose bush and tomoato plant bought respectively

7 0
4 years ago
Solve for t: <br> -48t + 2 &lt; -71t + 14
Nata [24]

Answer:

23t+2<14

-2<-2

23t< 12

t <12/23

4 0
3 years ago
Find the area enclosed by the x-axis and the curve x = 4 + et, y = t − t2.
Dominik [7]

Find where the curve intersects the <em>x</em>-axis; this happens when <em>y</em> = 0:

<em>y</em> = <em>t</em> - <em>t</em> ² = 0   →   <em>t</em> (1 - <em>t</em> ) = 0   →   <em>t</em> = 0, <em>t</em> = 1

Then the area of the bounded region is

\displaystyle\int_0^1 y(t) x'(t)\,\mathrm dt=\int_0^1 (t-t^2)e^t\,\mathrm dt=\boxed{3-e}

(you can compute the integral by parts)

7 0
3 years ago
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