Try this solution:
1. Note, that 100 is divisible by 4, and 999 is not divisible by it, only 996. This is an arithmetic sequence.
2. a1;a2;a3;a4;...a(n) the sequence, where a1=100; a2=104; a3=108; a4=112; ... etc., and a(n)=996. n=?
3. using a formula for n-term of the sequence: a(n)=a1+d(n-1), where a(n)=996; a1=100 and d=4 (according to the condition ' is divisible by 4'). Then 100+4(n-1)=996; ⇒ 4n=900; ⇒ n=225 (including 100).
answer: 225
Answer:
11+6=17
Step-by-step explanation:
Pretty sure its number 2, 8m do you need the whole process?
Answer:
Step-by-step explanation:
The time intervals are [0.00, 0.10], [0.10, 0.30], and [0.30, 0.60].
The rate of change in each interval is the slope of the line between the endpoints:
m = [f(b) − f(a)] / (b − a)
Filling out the table:
![\left[\begin{array}{ccc}Time (s)&Height (ft)&Rate\ of\ change(ft/s)\\0.00&96.44\\&&\frac{97.60-96.44}{0.10-0.00}=11.6 \\0.10&97.60\\&&\frac{98.57-97.60}{0.30-0.10}=4.85\\0.30&98.57\\&&\frac{98.30-98.57}{0.60-0.30}=-0.90\\0.60&98.30\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7DTime%20%28s%29%26Height%20%28ft%29%26Rate%5C%20of%5C%20change%28ft%2Fs%29%5C%5C0.00%2696.44%5C%5C%26%26%5Cfrac%7B97.60-96.44%7D%7B0.10-0.00%7D%3D11.6%20%5C%5C0.10%2697.60%5C%5C%26%26%5Cfrac%7B98.57-97.60%7D%7B0.30-0.10%7D%3D4.85%5C%5C0.30%2698.57%5C%5C%26%26%5Cfrac%7B98.30-98.57%7D%7B0.60-0.30%7D%3D-0.90%5C%5C0.60%2698.30%5Cend%7Barray%7D%5Cright%5D)
The intervals are already in order from greatest to least. Simply reverse the order to get least to greatest:
[0.30, 0.60]
[0.10, 0.30]
[0.00, 0.10]