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3 years ago

Regina makes skirts which need 3/4 ounces of beads per skirt. She has 5 5/14 ounces of beads, how many can she make?

Mathematics

1 answer:

Alex3 years ago

7 0

3/4 - per skirt >> 0.75
5 5/14 - unused >> 5.36 (approximately)

5.36/0.75= 7.14666...

Regina can make 7 skirts

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Find the sum of 3b/b 2 and 12/b 2 and express it in simplest form

alexandr1967 [171]

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3 years ago

A 15 foot flagpole casts an 11 foot shadow. At the exact same time a 28 foot tree casts a shadow. Which proportion would correct

marishachu [46]

The longer an object, the longer the shadow they cast at a given time of the day and vice versa. This is called direct proportionality. At the same time,

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3 years ago

Diameter is 22.5m. Calculate the area (round your answer to 2 decimal places). Use 3.14 for Pi.

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3 years ago

Sally had 2/9 of a cup of pudding as a snack after school and she had 1/4 of a cup of pudding as dessert after dinner. Sally est

IrinaK [193]

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3 years ago

A random sample of 16 one-kilogram sugar packets is obtained and the actual weights of the packets are measured. The sample mean

elena55 [62]

Answer:

The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.

Step-by-step explanation:

We are in posession of the sample's standard deviation, so we use the student's t-distribution to find the confidence interval.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 16 - 1 = 15

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 35 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.99}{2} = 0.905([tex]t_{995}$ ). So we have T = 2.9467

The margin of error is:

M = T*s = 2.9467*0.058 = 0.171

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 1.053 - 0.171 = 0.882kg

The upper end of the interval is the sample mean added to M. So it is 1.053 + 0.171 = 1.224 kg.

The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.

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3 years ago