The three consecutive terms in an AP are (k+1) ,3k and (4k+2)
We know that
If a,b,c are the three consecutive terms in an AP then b = (a+c)/2
now ,
Let a = k+1 , b = 3k and c = 4k+2
⇛3k = (k+1+4k+2)/2
⇛3k = (5k+3)/2
⇛2×3k = 5k+3
⇛6k = 5k+3
⇛ 6k-5k = 3
⇛ k = 3
The value of k = 3
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Answer:
the answer is 16.3452
Step-by-step explanation:
I hope it was helpful
The acceleration if the object when force is 100N is 10 meters per seconds squared
<h3>How to find the acceleration of the object</h3>
Given the direct variation relationship
force , f α acceleration, a
f = ka
k = constant of variation
solving for k
90 = k * 9
k = 90/9
k = 10
when force is 100N
100 = 10 * a
a = 100 / 10
a = 10
Learn more about acceleration here:
brainly.com/question/25749514
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The intersection of the steps is just a fancy way of asking wi\hich numbers are in both equations so lets look and see :)
The 1st = 0...1...5...7...8
The 2nd =0........5...7........9
Answer = D {0, 5, 7}
Hope this helps have any questions let me know :)
