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WARRIOR [948]
3 years ago
12

-1 80/99 needs to get to a decimal

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
4 0
-1.808080808080808
There u go
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1 ½ x 4 2/9 = <br><br> 2 ⅘ x ⅕ = <br><br> 4 3/7 x ⅚ =<br><br> 6/6 x 1 ¼ = 1 ¼
irina [24]
For the first 6 1/3
second is 14/25
third 2 29/42
 
7 0
3 years ago
These data represent the volumes in cubic yards of the largest dams in the united states and in South America. Construct a boxpl
Vsevolod [243]

Answer:

Check it below

Step-by-step explanation:

1) The Boxplot is a visual tool to easily find the quartiles of a Distribution. To construct a boxplot it's necessary to organize the data, find at least the upper (3rd Quartile) and lower quartile (1st Quartile), and register the maximum and the minimum value.

2) This graph confirms that the South American ones have much more water than the North American counterparts. Notice the Upper Quartile, (the top of the box) for the Southern ones, it's over 100,000 yrds³. And Compare to the Northern one.

4 0
3 years ago
Suppose there is a pile of quarters dimes and pennies with a total value of $1.07 how much of each coin can be present without b
Korolek [52]
Hello,

Very nice as problem.

2 solutions:
1 quater,8 dimes, 2 pennies
and
3 quaters,3 dimes, 2 pennies

since
107=( 0, 0, 107) but : 100= 0*25+ 0*10+ 100
107=( 0, 1, 97) but : 100= 0*25+ 1*10+ 90
107=( 0, 2, 87) but : 100= 0*25+ 2*10+ 80
107=( 0, 3, 77) but : 100= 0*25+ 3*10+ 70
107=( 0, 4, 67) but : 100= 0*25+ 4*10+ 60
107=( 0, 5, 57) but : 100= 0*25+ 5*10+ 50
107=( 0, 6, 47) but : 100= 0*25+ 6*10+ 40
107=( 0, 7, 37) but : 100= 0*25+ 7*10+ 30
107=( 0, 8, 27) but : 100= 0*25+ 8*10+ 20
107=( 0, 9, 17) but : 100= 0*25+ 9*10+ 10
107=( 0, 10, 7) but : 100= 0*25+ 10*10+ 0
107=( 1, 0, 82) but : 100= 1*25+ 0*10+ 75
107=( 1, 1, 72) but : 100= 1*25+ 1*10+ 65
107=( 1, 2, 62) but : 100= 1*25+ 2*10+ 55
107=( 1, 3, 52) but : 100= 1*25+ 3*10+ 45
107=( 1, 4, 42) but : 100= 1*25+ 4*10+ 35
107=( 1, 5, 32) but : 100= 1*25+ 5*10+ 25
107=( 1, 6, 22) but : 100= 1*25+ 6*10+ 15
107=( 1, 7, 12) but : 100= 1*25+ 7*10+ 5
107=( 1, 8, 2) is good
107=( 2, 0, 57) but : 100= 2*25+ 0*10+ 50
107=( 2, 1, 47) but : 100= 2*25+ 1*10+ 40
107=( 2, 2, 37) but : 100= 2*25+ 2*10+ 30
107=( 2, 3, 27) but : 100= 2*25+ 3*10+ 20
107=( 2, 4, 17) but : 100= 2*25+ 4*10+ 10
107=( 2, 5, 7) but : 100= 2*25+ 5*10+ 0
107=( 3, 0, 32) but : 100= 3*25+ 0*10+ 25
107=( 3, 1, 22) but : 100= 3*25+ 1*10+ 15
107=( 3, 2, 12) but : 100= 3*25+ 2*10+ 5
107=( 3, 3, 2) is good
107=( 4, 0, 7) but : 100= 4*25+ 0*10+ 0



4 0
3 years ago
For what values (cases) of the variables the expression does not exist: <img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4y%2B
stealth61 [152]

Answer:

y = - \frac{1}{2}

Step-by-step explanation:

Given

\frac{3}{4y+2}

The denominator of the expression cannot be zero as this would make it undefined. Equating the denominator to zero and solving gives the value that y cannot be, that is

4y + 2 = 0 ( subtract 2 from both sides )

4y = - 2 ( divide both sides by 4 )

y = \frac{-2}{4} = - \frac{1}{2} ← excluded value

6 0
3 years ago
How many segments have the midpoint (2, -3).Explain your reasoning.
Amanda [17]
Need a little bit more information to be able to answer the question
4 0
3 years ago
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