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3 years ago

Find two consecutive whole numbers that 52 lies between.

2 answers:

3 0

<span>Think about which perfect squares lies on the immediate left of 52 and which lies on the immediate right of 52. 49 ---- 52 ------- 64 After that, take the square roots of each of the three numbers.</span>

Anna [14]3 years ago

3 0

Im going to go with a wild guess and say 49 and 64

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Segment ET is a median of triangle FGE. Find the length of segment GT if GF=12.

yarga [219]

Answer: The length of segment GT is 6

Step-by-step explanation: Have a nice day!✌️

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2 years ago

How would i solve this?

Flauer [41]

Answer: C

Step-by-step explanation:

The enequality includes x values equal to or greater than -2 and less than(but not equal to) 1.

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3 years ago

The Venn Diagram below models probabilities of three events, A,B, and C.

Keith_Richards [23]

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Step-by-step explanation:

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2 years ago

Read 2 more answers

5. Lauren is saving for gymnastics camp, Camp costs $225 to attend. She has 40 percent of the money saved. How much money has sh

barxatty [35]

To solve this problem you have to convert the percentage to a decimal which would
be .40.

40% =40/100=.40

After doing so all you need to do is divide the amount needed by the percentage which gives you the amount she has saved.

225/.40= $90

Lauren has $90 saved

3 0

3 years ago

Leno4ka [110]

Answer:

$\frac{s^2-25}{(s^2+25)^2}$

Step-by-step explanation:

Let's use the definition of the Laplace transform and the identity given: $\mathcal{L}[t \cos 5t]=(-1)F'(s)$ with $F(s)=\mathcal{L}[\cos 5t]$ .

Now, $F(s)=\int_0 ^{+ \infty}e^{-st}\cos(5t) dt$ . Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that $F(s)=\frac{1}{5}\sin(5t)e^{-st} |_{0}^{+\infty}+\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt=\int_0 ^{+ \infty}e^{-st}\sin(5t) dt$ .

Using integration by parts again with u=e^(-st) and dv=sin(5t), we obtain that

$F(s)=\frac{s}{5}(\frac{-1}{5}\cos(5t)e^{-st} |_{0}^{+\infty}-\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}(\frac{1}{5}-\frac{s}{5}\int_0^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}-\frac{s^2}{25}F(s)$ .

Solving for F(s) on the last equation, $F(s)=\frac{s}{s^2+25}$ , then the Laplace transform we were searching is $-F'(s)=\frac{s^2-25}{(s^2+25)^2}$

3 0

2 years ago