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Anit [1.1K]
3 years ago
11

Need help answering these two questions

Mathematics
1 answer:
Nat2105 [25]3 years ago
7 0
3.55 for number 16.


Add up the x and z then take that sum and subtract it from the original amount.
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t takes about 14 person-hours of labor to break up a driveway and clear away the rubble. It takes about 8 person-hours of labor
Ostrovityanka [42]
For this case what you must do is add the number of hours to perform the different activities.
 We have then:
 14 person-hours of labor to break up to driveway and clear away the rubble.
 8 person-hours of labor to pour and smooth concrete for the new driveway.
 Adding both activities we have
 14 + 8 = 22
 answer
 it takes to break up to driveway, clear away the rubble, pour the concrete, and smooth the concrete about 22 person-hours of labor
4 0
3 years ago
Read 2 more answers
Kim saved $25 in 9 weeks. At that rate, how long will it take Kim to save $175?
Simora [160]

Answer:

it would take 63 weeks to save that much money

Step-by-step explanation:

divide 25 by 9 and get 2.7 then multiply 2.7 by 63 to get 175

3 0
3 years ago
A dice is rolled, then a coin is tossed.what is the probability of getting 5 then tails?
ivanzaharov [21]
Getting a 5 = 1/6
Getting tails = 1/2

1/6 * 1/2 = 1/12 
7 0
3 years ago
Read 2 more answers
Find the surface area of each solid figure
nasty-shy [4]

Answer:

Step-by-step explanation: i cant help if you dont give the question:)

7 0
4 years ago
∆ ABC is similar to ∆DEF and their areas are respectively 64cm² and 121cm². If EF = 15.4cm then find BC.​
lyudmila [28]

{\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}

★ ∆ ABC is similar to ∆DEF

★ Area of triangle ABC = 64cm²

★ Area of triangle DEF = 121cm²

★ Side EF = 15.4 cm

{\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}

★ Side BC

{\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}

Since, ∆ ABC is similar to ∆DEF

[ Whenever two traingles are similar, the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides. ]

\therefore \tt \boxed{  \tt \dfrac{area( \triangle \: ABC )}{area( \triangle \: DEF)} =  { \bigg(\frac{BC}{EF} \bigg)}^{2}   }

❍ <u>Putting the</u><u> values</u>, [Given by the question]

• Area of triangle ABC = 64cm²

• Area of triangle DEF = 121cm²

• Side EF = 15.4 cm

\implies  \tt  \dfrac{64   \: {cm}^{2} }{12 \:  {cm}^{2} }  =  { \bigg( \dfrac{BC}{15.4 \: cm} \bigg) }^{2}

❍ <u>By solving we get,</u>

\implies  \tt    \sqrt{\dfrac{{64 \: cm}^{2} }{ 121 \: {cm}^{2} }}   =   \bigg( \dfrac{BC}{15.4 \: cm} \bigg)

\implies  \tt    \sqrt{\dfrac{{(8 \: cm)}^{2} }{  {(11 \: cm)}^{2} }}   =   \bigg( \dfrac{BC}{15.4 \: cm} \bigg)

\implies  \tt    \dfrac{8 \: cm}{11 \: cm}    =   \dfrac{BC}{15.4 \: cm}

\implies  \tt    \dfrac{8  \: cm \times 15.4 \: cm}{11 \: cm}    =   BC

\implies  \tt    \dfrac{123.2 }{11 } cm   =   BC

\implies  \tt   \purple{  11.2 \:  cm}   =   BC

<u>Hence, BC = 11.2 cm.</u>

{\large{\textsf{\textbf{\underline{\underline{Note :}}}}}}

★ Figure in attachment.

\rule{280pt}{2pt}

4 0
2 years ago
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