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Eva8 [605]
4 years ago
10

Describe what information would be needed if you wanted to prove triangle BAC~triangle DFE. Be specific with side lengths, angle

names and the postulate that you use. PLEASE MAKE IT SIMPLE!!! I've tried to ask this question before but it ended in mass confusion!

Mathematics
1 answer:
MaRussiya [10]4 years ago
3 0

Refer to my drawing . Unlike most textbook problems, the triangles were drawn to scale. Side lengths 2a and side 2b are indeed proportional to side lengths a and b, respectively. It is obvious that the triangles are not similar. This is a counterexample that proves SS Similarity does not hold true. 

There is no SS Similarity. 

There is SAS Similarity. 


To prove two triangles similar you need one of the following three situations: 

1. The lengths of three sides of one triangle proportional to lengths of the three sides of the other triangle. (SSS Similarity Theorem) 

2. Two angles of one triangle congruent to two angles of another triangle. (AA SImilarity Theorem) 

3. The lengths of two sides of one triangle proportional to the lengths of two sides of another triangle, and their included angles congruent. (SAS Similarity Theorem)

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Can someone please help me out with this
Sliva [168]

Answer:

hope it helps

4 0
3 years ago
The polygons are similar. Find the missing side length.
zloy xaker [14]

Answer:

44

Step-by-step explanation:

Since triangles are similar, so their corresponding sides would be in proportion.

Therefore,

\frac{24}{32}  =  \frac{33}{?}  \\  \\  \\ ? =  \frac{32 \times 33}{24}  \\  \\ ? =  \frac{4\times 33}{3} \\  \\ ? =  4\times 11 \\  \\  ? =  44 \: units

6 0
3 years ago
=
ivann1987 [24]

9514 1404 393

Answer:

  • large: 55 lb
  • small: 30 lb

Step-by-step explanation:

Let x and y represent the weights of the large and small boxes, respectively. The problem statement gives rise to the system of equations ...

  x + y = 85 . . . . . combined weight of a large and small box

  70x +50y = 5350 . . . . combined weight of 70 large and 50 small boxes

We can subtract 50 times the first equation from the second to find the weight of a large box.

  (70x +50y) -50(x +y) = (5350) -50(85)

  20x = 1100 . . . . simplify

  x = 55 . . . . . . . divide by 20

Using this in the first equation, we can find the weight of a small box.

  55 +y = 85

  y = 30 . . . . . . . subtract 55

A large box weighs 55 pounds; a small box weighs 30 pounds.

4 0
3 years ago
Write an equation of a line going through (5,7) and (4 , -4)
Ostrovityanka [42]

Answer:

The equation of this line would be y = 11x - 48

Step-by-step explanation:

To get this equation, we first have to find the slope. We do that with the slope eqaution.

m(slope) = (y2 - y1)/(x2 - x1)

m = (-4 - 7)/(4 - 5)

m = -11/-1

m = 11

Now we can use this slope and either point in point-slope form to find the equation.

y - y1 = m(x - x1)

y - 7 = 11(x - 5)

y - 7 = 11x - 55

y = 11x - 48

6 0
3 years ago
Which expression is equivalent to Assume x > 0 and y 0.
Svetach [21]

we have

\sqrt{\frac{55x^{7}y^{6}}{11x^{11}y^{8}}}

we know that

\sqrt{\frac{55x^{7}y^{6}}{11x^{11}y^{8}}} =\sqrt{\frac{55}{11}\frac{x^{7}}{x^{11}}\frac{y^{6}}{y^{8}}} \\ \\= \sqrt{\frac{5}{x^{4} y^{2}}} \\ \\ =\frac{\sqrt{5}}{x^{2} y}

therefore

<u>the answer is</u>

The expression equivalent is  \frac{\sqrt{5}}{x^{2} y}

3 0
3 years ago
Read 2 more answers
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