What is the distance between the points (5, 6) and (5, 2)? a. 1 b. 3 c. 4 d. 8
1 answer:
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Answer:
30%
Step-by-step explanation:
Before starting to solve this question we have to understand the following. 1% is equal to one hundredth of something whole, and can be write as .
Now in order to solve this question we will first have to find a fraction that represent how much student out of the whole class choose hamburgers. We can easily find this fraction since the numerator of the fraction will be equal to the number of people that choose hamburgers and the denominator will be equal to the number of all students in the class. So we get......
Now in order to find out what percentage will this fraction equal to we will have make a fraction with the same value but with a denominator being 100. To do that we will have to understand the following......
(m is any number except 0)
The main I idea of this rule is that if we multiply the numerator and the denominator by the same number (any number except 0) we will get a fraction with the same value but with a different denominator and numerator.
So in our case we we do the following.........
(multiply both numerator and the denominator by 10 and we get...)
Now if we go back to what I said at the start of my explanation we will understand that another way of writing down is 30%.
Answer:
67.5feet
Step-by-step explanation:
Given parameters:
Model distance between building and gymnasium = 22.5 inches
Scale of model : 1 inch = 3 feet
Unknown:
Actual ground distance = ?
To solve this problem, we first must understand the concept of scale. A scale is a relationship that represents a dimension on a map/model compared to the true ground expression. In order to visualize or represent some real life objects on paper or in a computer, we use models. These models are an abstraction of the real world based on scales. There are different ways of representing a scale.
In this problem;
the scale is given as;
1 inch on model represents 3 feet on ground
Now, to find 22.5 inches, simply cross multiply and solve;
If 1 inch on model represents 3 feet on ground
22.5 inches on a model will be =
= 67.5feet
Therefore, the actual distance is 67.5feet