All categories

3 years ago

Solve for w w- 8=32 answer choices 4 24 40 256

Mathematics

2 answers:

Debora [2.8K]3 years ago

7 0

40 because 32+8 =40 and all your doing is solving for w which is like saying. what is 40 -32

crimeas [40]3 years ago

4 0

W = 40
Hope this helps!

You might be interested in

Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,

torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

$y=6x^2+14x$

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

$\frac{dy}{dx}=12x+14$

We know that length of curve

$s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx$

We have a=-2 and b=1

Using the formula

Length of curve= $s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx$

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

$dt=12dx$

$dx=\frac{1}{12}dt$

Length of curve= $s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt$

We know that

$\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C$

By using the formula

Length of curve= $s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})$

Length of curve= $s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})$

Length of curve= $s=32.66$

5 0

3 years ago

The world's largest pumpkin pie weighed 2020 pounds. The pie was 12 and one-third feet across and one-third foot thick. Write a

Yanka [14]

Answer:

$\frac{1}{3}$ = $\frac{2}{6}$

To find equivalent fractions, multiply be any number that is the same for the numerator/denominator

You can also divide, but it must be divisible by both the numerator/denominator

5 0

4 years ago

HELP ME PLEASE!!!! I NEED HELP!!!!!

ehidna [41]

I'm pretty sure the answer is A. hope that helped

8 0

3 years ago

Read 2 more answers

Pls help me solve it!

vekshin1

Answer:

A= 40°

B= 35°

C= 15°

Step-by-step explanation:

Since it says if the triangles were accurately drawn, then A would be the same degree as Q. C would be the same degree as P. B would be the same degree as R. Since R's degree is missing I knew that a obtuse triangle was 90°. I added 40+15 and got 55. Then i subtracted 90-55 and got 35. So the unknown value would be 35°.

I hope this helps.

3 0

4 years ago

Consider the following equation: f(x)=x^2+4\4x^2-4x-8 name the vertical asymptote(s)

zhenek [66]

ANSWER

The vertical asymptotes are

$\Rightarrow x=2\:or\:x=-1$