Answer:
a) 81.5%
b) 95%
c) 75%
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 266 days
Standard Deviation, σ = 15 days
We are given that the distribution of length of human pregnancies is a bell shaped distribution that is a normal distribution.
Formula:
a) P(between 236 and 281 days)
b) a) P(last between 236 and 296)
c) If the data is not normally distributed.
Then, according to Chebyshev's theorem, at least 
data lies within k standard deviation of mean.
For k = 2
Atleast 75% of data lies within two standard deviation for a non normal data.
Thus, atleast 75% of pregnancies last between 236 and 296 days approximately.
<span>The answer is 2 three-point shots. Since the Lakers made 37 two-point shots, one multiplies 37 by 2 (37 x 2), which equals 74. Then 74 is subtracted from the total 80 to see how many points are left (80 - 74), which equals 6. To determine the number of three-point shots, 6 is divided by 3 (6/3), which equals 2.</span>
The Answer To This Problem is: C.-4
Given
f(x)= -3x - 5
g(x)= 4x - 2
Find
(f - g)(x)
substitute the f and g values in (f - g)
(f - g)(x)= -3x - 5 - (4x - 2)
change the signs in parentheses because there is a negative sign in front of the parentheses
(f - g)(x)= -3x - 5 - 4x + 2
combine like terms
(f - g)(x)= -7x - 3
ANSWER: (f - g)(x)= -7x - 3
Hope this helps! :)
I believe the answer is C
