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3 years ago

Find the surface area of the prism or pyramid. Round to the nearest hundredth if necessary.

Mathematics

1 answer:

frutty [35]3 years ago

8 0

Answer:

the total surface area would be 233^2 im pretty sure (im not 100% sure) because the you do the lateral surface area add the top surface area add the bottom surface area so im pretty sure the answer would be 233cm^2 (^2 means squared)

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Mila [183]

Answer: The number pi is an irrational number

Step-by-step explanation:

Pi is irrational because it will never end and at the same time doesnt have a pattern in which the numbers repeat. Here are some of the numbers in pi 3.14159265359

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4 years ago

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3 years ago

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3 years ago

Convert the cartesian equations to a polar equation y=4x^2

alexdok [17]

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Step-by-step explanation:

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3 years ago

When a breeding group of animals is introduced into a restricted area such as a wildlife reserve, the population can be expected

jasenka [17]

Answer:

A. Initially, there were 12 deer.

B. N(10) corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.

C. After 15 years, there will be 410 deer.

D. The deer population incresed by 30 specimens.

Step-by-step explanation:

$N=\frac{12.36}{0.03+0.55^t}$

The amount of deer that were initally in the reserve corresponds to the value of N when t=0

$N=\frac{12.36}{0.33+0.55^0}$

$N=\frac{12.36}{0.03+1} =\frac{12.36}{1.03} = 12$

A. Initially, there were 12 deer.

B. $N(10)=\frac{12.36}{0.03 + 0.55^t} =\frac{12.36}{0.03 + 0.0025}=\frac{12.36}{y}=380$

B. N(10) corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.

C. $N(15)=\frac{12.36}{0.03+0.55^15}=\frac{12.36}{0.03 + 0.00013}=\frac{12.36}{0.03013}= 410$

C. After 15 years, there will be 410 deer.

D. The variation on the amount of deer from the 10th year to the 15th year is given by the next expression:

ΔN=N(15)-N(10)

ΔN=410 deer - 380 deer

ΔN= 30 deer.

D. The deer population incresed by 30 specimens.

8 0

3 years ago