Answer:
AM = 6
Step-by-step explanation:
Using the property of a parallelogram
• The diagonals bisect each other
MO is a diagonal, hence
AM = AO = 6
The last one if I'm not mistaking
The converted fractions are 3/12 and 5/12 and the sum is 2/3
<h3>How to convert the fractions?</h3>
From the question, the fractions are given as
1/4 and 5/12
The denominators of these fractions are
4 and 12
So. we start by calculating the LCD of the denominators
So, we have
4 = 2* 2
12 = 2 * 2 * 3
This gives
LCD = 2 * 2 * 3
Evaluate
LCD = 12
This means that the common denominator must be 12
So, we have
1/4 and 5/12
Multiply 1/4 by 3/3
This gives
3/12 and 5/12
When the fractions are added, we have
3/12 + 5/12 = (3 + 5)/12
Evaluate
3/12 + 5/12 = 8/12
Reduce fraction
3/12 + 5/12 = 2/3
Hence, the sum of the fractions is 2/3
Read more about fractions at
brainly.com/question/1622425
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Answer and Step-by-step explanation:
(a) Given that x and y is even, we want to prove that xy is also even.
For x and y to be even, x and y have to be a multiple of 2. Let x = 2k and y = 2p where k and p are real numbers. xy = 2k x 2p = 4kp = 2(2kp). The product is a multiple of 2, this means the number is also even. Hence xy is even when x and y are even.
(b) in reality, if an odd number multiplies and odd number, the result is also an odd number. Therefore, the question is wrong. I assume they wanted to ask for the proof that the product is also odd. If that's the case, then this is the proof:
Given that x and y are odd, we want to prove that xy is odd. For x and y to be odd, they have to be multiples of 2 with 1 added to it. Therefore, suppose x = 2k + 1 and y = 2p + 1 then xy = (2k + 1)(2p + 1) = 4kp + 2k + 2p + 1 = 2(kp + k + p) + 1. Let kp + k + p = q, then we have 2q + 1 which is also odd.
(c) Given that x is odd we want to prove that 3x is also odd. Firstly, we've proven above that xy is odd if x and y are odd. 3 is an odd number and we are told that x is odd. Therefore it follows from the second proof that 3x is also odd.
Perimeter=4h+4
If the base is 2 more than the height, it gives us the equation:
b=h+2
The equation for the perimeter of a rectangle can be though of as 2b+2h, so substituting in (h+2) for b from the first equation, we get 2(h+2)+2h.
This can be simplified to be 2h+4+2h or 4h+4
