Enter the quadratic equation
1 answer:
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Hey there!
For this problem, I would assume that you must make your own chart of values. You can do this by simply plugging in numbers like 1, 2, 3, etc... Since your graph won't be linear, you might want to do some negative numbers, as well.
Also because your graph isn't linear, you might want to figure out or determine on your own just how far your curve will go. You can then figure out how many times you need to plug in an additional numbers for your function to then graph.
I've attached a digital graph of this function, perhaps you can find it useful.
Hope this helped you out! :-)
For this problem, I would assume that you must make your own chart of values. You can do this by simply plugging in numbers like 1, 2, 3, etc... Since your graph won't be linear, you might want to do some negative numbers, as well.
Also because your graph isn't linear, you might want to figure out or determine on your own just how far your curve will go. You can then figure out how many times you need to plug in an additional numbers for your function to then graph.
I've attached a digital graph of this function, perhaps you can find it useful.
Hope this helped you out! :-)
Respuesta:
A.) BA = 12 m
Explicación paso a paso:
Usando triángulos similares:
BA / AC = DE / EC
BA = x; AC = 20; DE = 3; EC = 5
POR ESO ; TENEMOS :
x / 20 = 3/5
Multiplicar en cruz:
5 * x = 20 * 3
5 veces = 60
5x / 5 = 60/5
x = 12
