<h3>
Answer: Choice C. (2x - 6i)(x + 3i)</h3>
Work Shown:
2x^2 + 18
2(x^2 + 9)
2(x - 3i)(x + 3i) .... see note below
(2x - 6i)(x + 3i)
Note: I used the rule that a^2 + b^2 = (a - bi)(a + bi). I recommend FOILing out the right hand side to confirm the equation is true. You'll use the idea that i^2 = -1.
(x²+4x-12)/(x-2)=0
(x+6)(x-2)/(x-2)=0
x+6=0
x=-6
(-6,0)
What do you think the answer to the question is?
hope this helps! ask if you have anymore questions
They result in the same equation
rewrite it:
2y = 4x +18
3y = 6x + 27
divide so that you have only y
y = 2x + 9
y = 2x + 9
