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3 years ago

On a given day, 36 of the 445 students in a school were absent. What was the appproximate absentee rate that day?

Mathematics

1 answer:

Nata [24]3 years ago

5 0

Answer: The approximate absentee rate that day would be 8.09%.

Step-by-step explanation:

Since we have given that

Number of students who were absent = 36

Total number of students = 445

We need to find the approximate absentee rate that day :

Rate of absentee of that day would be

$\dfrac{\text{Number of absentee}}{\text{Total number of students}}\times 100\\\\=\dfrac{36}{445}\times 100\\\\=8.09\%$

Hence, the approximate absentee rate that day would be 8.09%.

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You are helping Folsom's city manager adjust traffic patterns for the new residents south of Hwy 50. A traffic light changes eve

Nikolay [14]

Answer:

120 minutes

Yes my answer makes sense

Step-by-step explanation:

This question has to do with Lowest Common Multiples

1) After how many minutes will both lights change at the same time again?

Step 1

We would find and list multiples of each number until the first common multiple is found.

Multiples of 30:

30, 60, 90, 120, 150, 180

Multiples of 40:

40, 80, 120, 160, 200

Step 2

The first common multiple of 30 aand 40 is the lowest common multiple.

Therefore,

LCM(30, 40) = 120

Therefore, both lights will change at the same time after 120 minutes.

2) Why does your answer make sense?

Lowest common multiple is a methodology used in mathematics to show the relationship between two numbers based on their multiples.

My answer makes sense because the only way both traffic light would come up at the same time can only be determined using the methodology of Lowest Common Multiple.

Hence, both lights will change at the same time after 120 minutes.

3 0

3 years ago

For three consecutive years, Sam invested some money at the start of the year. The first year, he invested x dollars. The second

wariber [46]

To answer we let x be the amount of money that Sam invested during the first year.

Below are the expressions translated from the given word forms for the amount invested.

Sam:
2nd year : amount = 5x/2 - 2000
3rd year : amount = x/5 + 1000

The sum of money invested by Sam is:
x + (5x/2 - 2000) + (x/5 + 1000)

Similarly, we derive the expressions that we use for the amount that Sally invested.
Sally
1st year : amount = 3x/2 - 1000
2nd year : amount = 2x - 1500
3rd year : amount = x/4 + 1400

The total amount that Sally invested is,
total = (3x/2 - 1000) + (2x - 1500) + (x/4 + 1400)

Equating the two equations:
(x) + (5x/2 - 2000) + (x/5 + 1000) = (3x/2 - 1000) + (2x - 1500) + (x/4 + 1400)

Solving for x,
x = 2000
For Sally's investment in the third year:
amount = x/4 + 1400 = (2000/4 + 1400) = 1900

ANSWERS:
Sam's first year = $2000
Sally's third year = $1900

3 0

4 years ago

in January, Dawn earns $9.25 allowance. She earns 3 times as much in February. If during March, she earns $5.75 more than she di

AURORKA [14]

Jan: 9.25
Feb: 9.25 x 3 = 27.75
March: 27.75 + 5.75 = 33.50

Dawn earns $33.50

8 0

3 years ago

Read 2 more answers

The length of the shorter side of a parallelogram is 29 cm. Perpendicular line segment, which goes through the point of intersec

Katena32 [7]

A = 900 $cm^{2}$

The area of a parallelogram can be found by taking its base (b) and multiplying by the height (h). The base has the measure of 33 +12 = 45 cm. Now, you just need to find the height of the parallelogram. The height can be found by using the pythagorean theorem ( $a^{2} + b^{2} = c^{2}$ .

So, when simplified the height of the parallelogram will be found from $\sqrt{ 29^{2} - 21^{2}}$

The height is 20 cm. The base is 45 cm. 45 x 20 = 900.

6 0

3 years ago

I don't get this pls help

dmitriy555 [2]

Answer:

d, e

Step-by-step explanation:

The applicable rules of exponents are ...

(a^b)(a^c) = a^(b+c)

a^-b = 1/a^b

In this case, it means the product is ...

(6^1)(6^0)(6^-3) = 6^(1+0-3) = 6^-2 = 1/6^2 = 1/36

The 6 without an exponent is equivalent to 6^1, an exponent of 1.

The sum of the exponents is -2.

Add the exponents to simplify the expression.

The value of the expression is 1/36.

An equivalent is any expression that results in 6^-2. One such is (6^5)(6^-7).

Only the last two choices, d and e, apply.

3 0

3 years ago