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3 years ago

Find x in the following triangle pls solve it fast!! Correct answer will get brainliest!!!!

Mathematics

1 answer:

neonofarm [45]3 years ago

4 0

Answer:

c=26

Step-by-step explanation:

So you would use the formula a^2+b^2=c^2

10^2+24^2=c^2

100+576=c^2

C^2=676

c=26

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Identify the percent rate of change in exponential function y=(0.9)

Papessa [141]

Answer:

Step-by-step explanation:

0.9 multiplied by 100 to turn it into a percentage is 90.

5 0

2 years ago

Read 2 more answers

Which expressions is equivalent -8.2-5

GuDViN [60]

Answer:

-13.2

Step-by-step explanation:

-8.2-5 essentially means that you just have to add 8.2 and 5. (disregard the signs for a moment) if you add them you get 13.2 as both of these number have a negative sign just add it and here's your answer

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3 years ago

Rewrite the expression as an equivalent ratio of logs using the indicated base.log17(52.875) to base 10.

s2008m [1.1K]

Answer:

$log_{17}52.875 = log_{10}52.875 : log_{10}17}$

Step-by-step explanation:

Given

$log_{17}(52.875)$

Required

Convert to base 10

To do this, we make use of the following logarithm laws;

$log_ba = \frac{log_{10}a}{log_{10}b}$

In the given parameters;

$a = 52.875$

$b = 17$

Substitute these values in $log_ba = \frac{log_{10}a}{log_{10}b}$

$log_{17}52.875 = \frac{log_{10}52.875}{log_{10}17}$

Represent as a ratio

$log_{17}52.875 = log_{10}52.875 : log_{10}17}$

Hence;

$log_{17}(52.875)$ is represented as $log_{17}52.875 = log_{10}52.875 : log_{10}17}$

7 0

3 years ago

The temperature startedat 10 degrees F. The temperature dropped 5

gavmur [86]

Answer:

-5FStep-by-step explanation:

10-5x3=-5 F

7 0

3 years ago

Two owners of a cattle ranch, Jo and Val, want to find the average weight for the ranch's 200 cows. Instead of weighing all of t

Zolol [24]

Answer:

The value is $E =19.6$

Step-by-step explanation:

From the question we are told that

The mean of Jo cows is $\= x_1 = 1350$

The standard deviation of Jo cow is $s_1 = 50$

The mean of Val cows is $\= x_2 = 1420$

The standard deviation of Val cows is $s_2 = 50$

The sample size for both Val and Jo is n = 25

Let assume that the level of significance is $\alpha = 0.05$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

Hence margin of error for Jo is

=> $E = 1.96 * \frac{50}{\sqrt{25} }$

=> $E =19.6$

4 0

3 years ago