The code is first declaring array1 as a new array of integers with length 25. Then the comment tells us that somewhere in the middle of the code, values are given to each element of array1.
Lastly, we are iterating through the array using a for loop. We start at index 0, and continue until the index value (a) is one less than the length of the array. So array1[a] will give us the value that was assigned to the element at index a.
In the for loop, we are adding the value of array[a] to the integer "value" which was initialized as 0. Therefore, the result will be the sum of all the integers in array1.
Answer:
a. 100%
b. 50%
c. 66.6%
Explanation:
a.
The memory references D6, 58, D8, 9A, DE and 5C all results in misses and the miss ratio is 100 (that is , 6 misses/ 6 references*100 = 100%)
b.
If fully associative cache is used, there will be a 3 cache misses with miss ratio of (3/6*100) = 50%.
c.
With a 2-way set-associative cache, 4 memory reference misses will occur, with a miss ratio of (4/6*100)= 66.6% misses.
Answer: 50
Explanation: let amit's current age = a and armaan's current age be b.
(a-5) = 3* (b-5)
i.e. a= 3b-10 -(i)
10 years later,
(a+10) = 2(b+10)
i.e. a=2b+10 -(ii)
From eqn (i) and (ii),
b=20,
and a=50
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