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melomori [17]
3 years ago
15

A risk handling technique in which the organization chooses to simply do nothing, as the cost of the risk being actualized is lo

wer than the cost of the security control, is known as
a. Transfer
b. Avoidance
c. Acceptance
d. Mitigation
Computers and Technology
1 answer:
monitta3 years ago
6 0

Answer:

Option c Acceptance

Explanation:

Risk acceptance is one way of risk management. In risk management this is not always the case every risk must be addressed. In some cases, the risk is identified as tolerable and no further action is taken to mitigate the risk. Risk acceptance considers the impact of the risk can be accepted or at least not up to a point to spend the limited resource to control it.

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Write a function called median, that takes as parameter a full, sorted array of doubles and returns the median of the list. For
trapecia [35]

Answer:

Explanation:

public class Lab8

{

public static double median(double list[])

{

int size=list.length;

if(size%2!=0)

return list[size/2];

else

return(list[size/2-1]+list[size/2])/2.0;

}

public static boolean issorted(double list[])

{

for(int i=0;i<list.length-1;i++)

{

if(list[i]>list[i+1])

return false;

}

return true;

}

public static void findcommon(int a1[],int a2[],int common[])

{

int c=0;

for(int i=0;i<a1.length;i++)

{

boolean isFilled=false;

for(int j=0;j<c;j++)

{

if(a1[i]==common[j])

{

isFilled=true;

break;

}

}

if(isFilled)

{

for(int k=0;k<a2.length;k++)

{

if(a1[i]==a2[i])

{

common[c]=a1[i];

c++;

break;

}

}

}

}

while(c<common.length)

{

common[c]=0;

c++;

}

}

public static void rotateRight(int list[])

{

int temp=list[list.length-1];

for(int i=list.length-1;i>0;i--)

{

list[i]=list[i-1];

}

list[0]=temp;

}

public static int count(int list[],int n)

{

int ncount=0;

for(int i=0;i<list.length;i++)

{

if(list[i]==n)

ncount++;

}

return ncount;

}

public static int[] stretch(int list[])

{

int stretchedList[]=new int[list.length*2];

int k=0;

for(int i=0;i<list.length;i++)

{

int n=list[i];

if(n%2==0)

{

stretchedList[k]=n/2+1;

stretchedList[k+1]=n/2;

}

k+=2;

}

return stretchedList;

}

public static void printDoubleArray(double arr[])

{

System.out.print("[");

for(int i=0;i<arr.length;i++)

{

if(i!=arr.length-1)

System.out.print(arr[i]+",");

else

System.out.print(arr[i]);

}

System.out.println("]");

}

public static void printIntArray(int arr[])

{

System.out.print("[");

for(int i=0;i<arr.length;i++)

{

if(i!=arr.length-1)

System.out.print(arr[i]+",");

else

System.out.print(arr[i]);

}

System.out.println("]");

}

public static void main(String[] args)

{

double list1[]={1.1,2.2,3.3,4.4,5.5,6.6};

double med=median(list1);

System.out.println("List1:");

printDoubleArray(list1);

System.out.println("Median of List1:"+ med);

double list2[]={1.1,2.2,3.3,4.4,6.6,5.5};

boolean result=issorted(list2);

System.out.println("List2:");

printDoubleArray(list2);

System.out.println("List2 is a sorted array.(T/F):"+ result);

int list3[]={3,8,5,6,5,8,9,2};

int list4[]={5,15,4,6,7,3,9,11,9,3,12,13,14,9,5,3,13};

int list5[]=null;

if(list3.length<=list4.length)

list5=new int[list3.length];

else

list5=new int[list4.length];

findcommon(list3,list4,list5);

System.out.println("\n List3:");

printIntArray(list3);

System.out.println("\n List4:");

printIntArray(list4);

System.out.println("\n Array with common value,List5:");

printIntArray(list5);

int list6[]={3,8,19,7};

System.out.println("\n List6:");

printIntArray(list6);

rotateRight(list6);

System.out.println("\n the array after rotate right:");

printIntArray(list6);

int list7[]={3,5,2,1,92,38,3,14,5,73};

int n=count(list7,3);

System.out.println("\n List7:");

printIntArray(list7);

System.out.println("\n the number of occurences of the value 3 in the list 7:"+ n);

int list8[]={18,7,4,24,11};

int list9[]=stretch(list8);

printIntArray(list8);

System.out.println("\n The array after stretching:");

printIntArray(list9);

}

}

8 0
3 years ago
Which best describes a difference between transcription and DNA replication
ruslelena [56]
DNA replication is just making a copy of someone or somethings DNA
6 0
3 years ago
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GenXTech is a growing company that develops gaming applications for military simulations and commercial clients. As part of its
ki77a [65]

Answer:

an enterprise architecture

Explanation:

Based on the information provided within the question it can be said that in this scenario it seems that GenXTech is creating an enterprise architecture. This is a blueprint made for a company that illustrates and defines all the finer details regarding the structure and operation of an organization, as well as where the organization should be heading in order to achieve the business goals that have already been set.

6 0
3 years ago
What is this tool called?
kondor19780726 [428]
Is there a picture????????
4 0
3 years ago
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Explain what mistake Miranda made in the following scenario. Situation: Miranda suspects that there may be a problem with the ha
Dennis_Churaev [7]

Answer: Answer below.

Explanation:

I'm not fully sure myself, so don't agree with me fully.

I believe what she may have done wrong is tell the technician about a "program." A program doesn't have to do anything with physical hardware.

5 0
3 years ago
Read 2 more answers
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