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2 years ago

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Which of the following lists is in order from smallest to largest? 1.4, 1/4 ,14% 1/4 , 14%, 1.4 14%, 1/4 , 1.4 1.4, 14%, 1/4

1 answer:

777dan777 [17]2 years ago

5 0

Firstly, I noticed that there are fractions, decimals, and percents. I will change everything to percents, so it’s more easy for me to compare each of them.

List 1. 140%, 25%, 14%. This is from greatest to least, not least to greatest.
List 2. 25%, 14%, 14%. This is not from least to greatest, either.
List 3. 14%, 25%, 140%. This is from least to greatest.
List 4. 140%, 14%, 25%. This is not from least to greatest.

List 3 is from least to greatest. I got this answer by converting all of the fractions and decimals to percentages.

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Sammie and Joel invest their money with the Grabitall Bank.

AlekseyPX

a) Sammie earns
£320×4% = £12.80
each year.

Joel earns
£420×3% = £12.60
each year.

Sammie earns the most interest.

b) Joel's interest after 5 years is
£12.60×5 = £63
so the total amount of money Joel will have is
£420 +63 = £483

5 0

3 years ago

Someeee one?????????????????

Ad libitum [116K]

Answer:

Option B) $a_{n} = 2\cdot 4^{n-1}$

Step-by-step explanation:

The given geometric sequence is

2, 8, 32, 128,....

The general form of a geometric sequence is given by

$a_{n} = a_{1}\cdot r^{n-1}$

Where n is the nth term that we want to find out.

a₁ is the first term in the geometric sequence that is 2

r is the common ratio and can found by simply dividing any two consecutive numbers in the sequence,

$r=\frac{8}{2} = 4$

You can try other consecutive numbers too, you will get the same common ratio

$r=\frac{32}{8} = 4$

$r=\frac{128}{32} = 4$

So the common ratio is 4 in this case.

Substitute the value of a₁ and r into the above general equation

$a_{n} = 2\cdot 4^{n-1}$

This is the general form of the given geometric sequence.

Therefore, the correct option is B

Note: Don't multiply the first term and common ratio otherwise you wont get correct results.

Verification:

$a_{n} = 2\cdot 4^{n-1}$

Lets find out the 2nd term

Substitute n = 2

$a_{2} = 2\cdot 4^{2-1} = 2\cdot 4^{1} = 2\cdot 4 = 8$

Lets find out the 3rd term

Substitute n = 3

$a_{3} = 2\cdot 4^{3-1} = 2\cdot 4^{2} = 2\cdot 16 = 32$

Lets find out the 4th term

Substitute n = 4

$a_{4} = 2\cdot 4^{4-1} = 2\cdot 4^{3} = 2\cdot 64 = 128$

Lets find out the 5th term

Substitute n = 5

$a_{5} = 2\cdot 4^{5-1} = 2\cdot 4^{4} = 2\cdot 256 = 512$

Hence, we are getting correct results!

6 0

3 years ago

Please help i will thank and rate 5 star!

stich3 [128]

The sign of the product of that equation would be negative.

5 0

2 years ago

A car dealership purchased a car for $15,000. They mark up the price by 35%. What is the retail price of the vehicle

Snowcat [4.5K]

Answer: the answer is 20,250

Step-by-step explanation:

35% of 15,000 = 5,250

15,000+5250 = 20,250

4 0

2 years ago

Lelu [443]

Answer:

the correct answer is A. Because it shows the equal qualifient of the answer

4 0

3 years ago