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alukav5142 [94]
3 years ago
13

PLEASE HELP What is the volume of the prism below?

Mathematics
1 answer:
Tcecarenko [31]3 years ago
4 0
The volume of the prism is 646
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What’s the algebraic expression for this
Julli [10]

Answer:

1 3 6 10 15

Step-by-step explanation:

brainliest plz

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3 years ago
Evaluate the. Expression x+ 9, if x= 8. 1, 2, 17, 89
Solnce55 [7]

Answer:

17

Step-by-step explanation:

We are given the expression find x + 9 if x = 8.

When a certain number has a variable and the value of the variable is known, all you have to do is plug in the variable amount into the equation, therefore :

x is 8 , so we plug in 8 for x

x + 9 =

8 + 9 = 17

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3 years ago
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Order these fractions from least<br>to greatest.<br>2/30, 2/5, 2/4<br>​
zavuch27 [327]

Answer:

From least to greatest is 2/30, 2/5, 2/4

<em>Hope I Helped</em>

7 0
3 years ago
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F(x)=x^3+3
lawyer [7]

Answer:

  (a)   -3/4

  (b)  -0.75

  (c)  -0.75

Step-by-step explanation:

It's a bit hard to tell what constitutes an "iteration" when using the bisection method to approximate a polynomial root. For the purpose here, we'll say one iteration consists of ...

  • evaluating the function at the midpoint of the bracketing interval
  • choosing a smaller bracketing interval
  • identifying the x-value known to be closest to the solution

Thus, the result of the iteration consists of a bracketing interval and the choice of one of the interval's ends as the solution approximation.

__

(a) We observe that the graphs intersect in the interval (-1, 0). For the first iteration, we evaluate f(x)-g(x) at x=-1/2. This tells us the solution is in the interval (-1, -1/2). The x-value closest to the root is x=-1/2.

For the second iteration, we evaluate the function f(x)-g(x) at x=-3/4. This tells us the solution is in the interval (-1, -3/4). The x-value closest to the root is x=-3/4.

For the third iteration, we evaluate the function f(x)-g(x) at x=-7/8. This tells us the solution is in the interval (-7/8, -3/4). The x-value closest to the root is x=-3/4.

__

(b) The graph tells us the solution is approximately 0.7549. Rounded to 2 decimal places, the solution is approximately 0.75.

__

(c) The above solution found after 3 iterations rounded to 2 decimal places is exactly 0.75.

__

See the attached table for function values.

_____

<em>Comment on bisection iteration</em>

Since you cut the interval containing the root in half with each iteration, you gain approximately one decimal place for each 3 iterations. When the function value is very nearly zero at one of the interval endpoints, it can take many more iterations to achieve a better result.

Here, it takes 4 more iterations before an x-value becomes closer to the solution (x≈-97/128). And it takes one more iteration to move the end of the interval away from -3/4. After these 5 more iterations (8 total), the solution is known to lie in the interval (-97/128, -193/256). The corresponding solution approximation is -193/256. It is still only correct to 2 decimal places.

5 0
3 years ago
(Photo) Please help me!
SOVA2 [1]
Volume =πr²*h=π*7²*4=196π
answer B
3 0
3 years ago
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