Answer:
The answer is below
Step-by-step explanation:
Let S denote syntax errors and L denote logic errors.
Given that P(S) = 36% = 0.36, P(L) = 47% = 0.47, P(S ∪ L) = 56% = 0.56
a) The probability a program contains both error types = P(S ∩ L)
The probability that the programs contains only syntax error = P(S ∩ L') = P(S ∪ L) - P(L) = 56% - 47% = 9%
The probability that the programs contains only logic error = P(S' ∩ L) = P(S ∪ L) - P(S) = 56% - 36% = 20%
P(S ∩ L) = P(S ∪ L) - [P(S ∩ L') + P(S' ∩ L)] =56% - (9% + 20%) = 56% - 29% = 27%
b) Probability a program contains neither error type= P(S ∪ L)' = 1 - P(S ∪ L) = 1 - 0.56 = 0.44
c) The probability a program has logic errors, but not syntax errors = P(S' ∩ L) = P(S ∪ L) - P(S) = 56% - 36% = 20%
d) The probability a program either has no syntax errors or has no logic errors = P(S ∪ L)' = 1 - P(S ∪ L) = 1 - 0.56 = 0.44
Answer:
h = 9 cm.
Step-by-step explanation:
V = kBh where k is the constant of variation.
From the given info:
32 = k*16*6 = 96k
So k = 32/96 = 1/3.
So we have the equation of variation:
V = 1/3Bh
When V = 60 B = 20, so:
60 = 1/3 20h
20h = 60 * 3 = 180
h = 180 /20 = 9.
Answer:
Brenda
Step-by-step explanation:
You can divide the number of pages by the number of minutes to find the amount of minutes it takes to read 1 page. For Arnold, 3 pages / 7 minutes = 1 page per approximately 0.43 minutes. For Brenda, 8 pages / 14 minutes = 1 page per approximately 0.57 minutes. Brenda reads slightly faster since 0.57 > 0.43
7%
is the bigger number bc 0.7 is a decimal an it like ex.... 0.50th its like half of one whole percentage
do u see wat I mean
Answer:
7.25 × 10^6
Step-by-step explanation:
1) put into standard form: 6,000,000 + 1,250,000
2) add: 6,000,000 + 1,250,000= 7,250,000
3) put into scientific notation: 7.25 × 10^6
