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3 years ago

If f(n) = n2 - n, then f(-4) is _____. -20 20 12 -12

Mathematics

2 answers:

kolbaska11 [484]3 years ago

8 0

The correct option is "20" because

f(n)=n2−n
(−4)=(−4)2−(−4)
=16+4
=20

Alekssandra [29.7K]3 years ago

5 0

Answer:

The answer is 20.

Step-by-step explanation:

The answer of this question is applying the number -4 in the equation, this is:

$f(n)=n^{2} -n\\Replacing\\f(-4)=(-4)^{2} -(-4)\\f(-4)=16+4\\f(-4)=20$

The answer is 20.

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bazaltina [42]

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3 years ago

Determine the slope and y intercept. Y=3/2x+3

Harlamova29_29 [7]

Slope: 3/2 (the coefficient of x)

Y-Intercept: (0,3) (substituting x = 0 into the equation)

Ans: Yellow

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3 years ago

3 Find the value of a in the equation,(3+4√3)(2-a√3)=-18+2√3

ankoles [38]

Given:

The equation is:

$\left(3+4\sqrt{3}\right)\left(2-a\sqrt{3}\right)=-18+2\sqrt{3}$

To find:

The value of a.

Solution:

We have,

$\left(3+4\sqrt{3}\right)\left(2-a\sqrt{3}\right)=-18+2\sqrt{3}$

On simplification, we get

$(3)(2)+(4\sqrt{3})(2)+(3)(-a\sqrt{3})+(4\sqrt{3})(-a\sqrt{3})=-18+2\sqrt{3}$

$6+8\sqrt{3}-3a\sqrt{3}-4a(3)=-18+2\sqrt{3}$

$6+8\sqrt{3}-3a\sqrt{3}-12a=-18+2\sqrt{3}$

$(6-12a)+(8-3a)\sqrt{3}=-18+2\sqrt{3}$

On comparing both sides, we get

$6-12a=-18$

$-12a=-18-6$

$a=\dfrac{-24}{-12}$

$a=2$

And,

$8-3a=2$

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Therefore, the value of a is 2.

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3 years ago

The interior angles formed by the sides of a quadrilateral have measures that sum to 360°.

vova2212 [387]

add all the angles and make them equal to 360

88 + 108 + (3x-6) + 2x = 360

196 + 5x -6 = 360

190 + 5x = 360

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x = 34 = answer

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3 years ago