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kirill [66]
3 years ago
10

A bacteria sample can be modeled by the function f(x) - 350(1.20) which gives the number of bacteria in the sample at the end of

x days. Which statement is the best interpretation of one of the values in this function? 11) A) The initial number of bacteria is 350. B) The number of bacteria at the end of one day is 350. 9 The initial number of bacteria decreases at a rate of 20% D) The number of bacteria increases at a rate of 120% each day.
Mathematics
1 answer:
marissa [1.9K]3 years ago
3 0

Answer: A) The initial number of bacteria is 350.

Step-by-step explanation:

Exponential growth equation: f(x)=A(1+r)^x , where A=Initial value, r= growth rate.          (i)

Given: A bacteria sample can be modeled by the function f(x) = 350(1.20)which gives the number of bacteria in the sample at the end of x days.

Here, f(x)=350(1+0.20)

Compare this equation to  (i) , we get A = 350 and r= 0.20 = 20% (growth rate)

So, the  best interpretation of one of the values in this function are:

A) The initial number of bacteria is 350.

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If $12000 is invested in an account in which the interest earned is continuously compounded at a rate of 2.5%
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Complete Question

If $12000 is invested in an account in which the interest earned is continuously compounded at a rate of 2.5% for 3 years

Answer:

$ 12,934.61

Step-by-step explanation:

The formula for Compound Interest Compounded continuously is given as:

A = Pe^rt

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t = Time after t years = 3

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First, convert R percent to r a decimal

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The total amount from compound interest on an original principal of $12,000.00 at a rate of 2.5% per year compounded continuously over 3 years is $ 12,934.61.

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2 years ago
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Megan has $15,000 to invest. She is considering two investment options. Option A pays 3.2% simple interest. Option B pays 4.1% i
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wheee



Compute each option


option A: simple interest


simple interest is easy

A=I+P

A=Final amount

I=interest

P=principal (amount initially put in)


and I=PRT

P=principal

R=rate in decimal

T=time in years


so given

P=15000

R=3.2% or 0.032 in deecimal form

T=10


A=I+P

A=PRT+P

A=(15000)(0.032)(10)+15000

A=4800+15000

A=19800

Simple interst pays $19,800 in 10 years




Option B: compound interest

for interest compounded yearly, the formula is

A=P(1+r)^t

where A=final amount

P=principal

r=rate in decimal form

t=time in years


given

P=15000

r=4.1% or 0.041

t=10


A=15000(1+0.041)^{10}

A=15000(1.041)^{10}

use your calculator

A=22418.0872024

so after 10 years, she will have $22,418.09 in the compounded interest account





in 10 years, the investment in the simple interest account will be worth $19,800 and the investment in the compounded interest account will be worth$22,418.09

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