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Andrej [43]
3 years ago
6

How can I get Y result?5y+38 = 180

Mathematics
2 answers:
BaLLatris [955]3 years ago
7 0
5y+38=180 \\ \\ 5y=180-38 \\ \\ 5y=142 \\ \\ \boxed{y=\frac{142}{5}=28.4}
OleMash [197]3 years ago
4 0
<em>Simply subtract 38 from both sides,</em>

<em>5y + 38 - 38 = 180 - 38</em>

<em>5y = 142</em>

<span><em>Divide both sides by 5, to get y</em>

<em>y = 142 / 5  Answer</em></span>
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Factor 15abc − 9ab − 3bcd completely
goldenfox [79]
I believe the correct answer is C
3 0
3 years ago
Read 2 more answers
Solve and simplify 6 2/3 x 3 1 /2
sergeinik [125]

6 \frac{2}{3}   =  \frac{2}{18}  = 9

3 \times \frac{1}{2}  =  \frac{1}{6}  = 6

6×9=54

4 0
2 years ago
the ratio of boys to girls in janices classroom is 3:5, and there are a total of 32 students in the class, help plss​
svetoff [14.1K]

9514 1404 393

Answer:

  • 12 boys
  • 20 girls

Step-by-step explanation:

The total number of students (32) corresponds to the total number of ratio units (3+5 = 8), so each ratio unit represents 32/8 = 4 students.

The 3 ratio units representing boys will stand for 3×4 = 12 boys.

The 5 ratio units representing girls will stand for 5×4 = 20 girls.

There are 12 boys and 20 girls in Janice's classroom.

_____

<em>Additional comment</em>

I find the above solution to be the easiest.

You can also write a system of equations. Let b and g represent the numbers of boys and girls, respectively.

  b/g = 3/5

  b +g = 32

Multiplying the first equation by g gives an expression for b that can be substituted into the second equation:

  b = (3/5)g

  (3/5)g +g = 32

  8/5g = 32 . . . . . . . . . . . . . . . . . collect terms

  g = (5/8)(32) = 5·4 = 20 . . . . . . multiply by 5/8

  b = (3/5)(20) = 3·4 = 12 . . . . . . . find b using the value of g

5 0
2 years ago
The length, width, and height of a rectangular solid are 13.5, 12, and 14.1, respectively. Find the volume.
Finger [1]
You have to multiply the length by the width and the sum of that you will multiply by the height. In this case 13.5 times 12 is 162. So 162 times 14.1 is 2284.2
6 0
3 years ago
A rope of length 18 feet is arranged in the shape of a sector of a circle with central angle O radians, as shown in the
creativ13 [48]

Answer:

A(\theta)=\frac{162 \theta}{(\theta+2)^2}

Step-by-step explanation:

The picture of the question in the attached figure

step 1

Let

r ---> the radius of the sector

s ---> the arc length of sector

Find the radius r

we know that

2r+s=18

s=r \theta

2r+r \theta=18

solve for r

r=\frac{18}{2+\theta}

step 2

Find the value of s

s=r \theta

substitute the value of r

s=\frac{18}{2+\theta}\theta

step 3

we know that

The area of complete circle is equal to

A=\pi r^{2}

The complete circle subtends a central angle of 2π radians

so

using proportion find the area of the sector by a central angle of angle theta

Let

A ---> the area of sector with central angle theta

\frac{\pi r^{2} }{2\pi}=\frac{A}{\theta} \\\\A=\frac{r^2\theta}{2}

substitute the value of r

A=\frac{(\frac{18}{2+\theta})^2\theta}{2}

A=\frac{162 \theta}{(\theta+2)^2}

Convert to function notation

A(\theta)=\frac{162 \theta}{(\theta+2)^2}

6 0
3 years ago
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