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algol13
3 years ago
14

Given r(x) = x square +2x -1 and s(x) = x-1 what is the value of r(s(3))

Mathematics
1 answer:
Amanda [17]3 years ago
3 0

Answer:

r(s(3))=7

Step-by-step explanation:

we have

r(x)=x^{2} +2x-1

s(x)=x-1

we know that

The function composition is equal to

(r ∘ s )(x) = r(s(x))

In the function r(x) substitute the variable x by the function s(x)

so

r(s(x))=(x-1)^{2} +2(x-1)-1

For x=3

substitute the value of x=3 in the function composition

r(s(3))=(3-1)^{2} +2(3-1)-1

r(s(3))=(2)^{2} +2(2)-1

r(s(3))=4+4-1

r(s(3))=7

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Answer:

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The question is above in the picture​
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