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algol13
3 years ago
14

Given r(x) = x square +2x -1 and s(x) = x-1 what is the value of r(s(3))

Mathematics
1 answer:
Amanda [17]3 years ago
3 0

Answer:

r(s(3))=7

Step-by-step explanation:

we have

r(x)=x^{2} +2x-1

s(x)=x-1

we know that

The function composition is equal to

(r ∘ s )(x) = r(s(x))

In the function r(x) substitute the variable x by the function s(x)

so

r(s(x))=(x-1)^{2} +2(x-1)-1

For x=3

substitute the value of x=3 in the function composition

r(s(3))=(3-1)^{2} +2(3-1)-1

r(s(3))=(2)^{2} +2(2)-1

r(s(3))=4+4-1

r(s(3))=7

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Refer to the figure. Given a is parallel to be and 7 = 94, find the measure of the following angles.
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Answer :it is 9 tHere is ur answer
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2 years ago
What is the value of w?
Dima020 [189]
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F(x) = 2x + 3g(x) = 2x² + 6x + 13Find: (gºf)(x)
Butoxors [25]

Answer:

The function (gof)(x) is;

(g\circ f)(x)=8x^2+36x+49

Explanation:

Given the functions;

\begin{gathered} f(x)=2x+3 \\ g(x)=2x^2+6x+13 \end{gathered}

Solving for the function;

(g\circ f)(x)=g(f(x))

so, we have;

\begin{gathered} g(f(x))=2(f(x))^2+6(f(x))+13 \\ g(f(x))=2(2x+3)^2+6(2x+3)+13 \\ g(f(x))=2(4x^2+12x+9)^{}+6(2x)+6(3)+13 \\ g(f(x))=8x^2+24x+18^{}+12x+18+13 \\ g(f(x))=8x^2+24x^{}+12x+18+18+13 \\ g(f(x))=8x^2+36x+49 \end{gathered}

Therefore, the function (gof)(x) is;

(g\circ f)(x)=8x^2+36x+49

5 0
9 months ago
Will mark as brainliest if correct
lana [24]

Answer:

wala sa choices ang sagot.

ANS: 128

EXPLANATION

a(9)=14+2(9-1)

a(9)=14+2(8)

a(9)=16(8)

9= 128

yan sagot ko po

4 0
2 years ago
The weight of strawberries follows a normal distribution with a mean weight of 12 grams and a standard deviation of 2.5 grams. I
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This is a problem of Standard Normal distribution.

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So, from standard normal table we need to find the probability of z score to be less than -1.4. The probability comes out to be 0.0808

Thus, the <span>probability that the strawberry weighs less than 8.5 grams is 0.0808</span>
6 0
3 years ago
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