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Elena-2011 [213]
2 years ago
10

Points A, B, and C are located on a circle, and chords exist between all three points. If the measure of ∠BAC is 88°, what is th

e measure of BC?
Mathematics
1 answer:
goldfiish [28.3K]2 years ago
5 0
If the angle is an inscribed angle then it’s intercepted arc will be double the angles measurements. Therefore if the inscribed angle BAC is 88 degrees then it’s intercepted arc BC will be 176 degrees.
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Please help pleaseeee
Maksim231197 [3]

Answer:

False

Step-by-step explanation:

When you compare the dots to the numbers, you can see that the 5s and 8s don't match.

The dot plot has 6 5s, but the data has 5.

The dot plot has 2 8s, but the data has 1.

I hope this helps!

pls ❤ and give brainliest pls

8 0
3 years ago
Read 2 more answers
Alexia and Haley start out together to bike from Apple Valley to Hesperia, a distance of 15 miles. Alexia bikes at 5 miles per h
lilavasa [31]

I believe the answer is:

Alexia arrives 1 hour later than Hailey.


Good luck! XD

6 0
3 years ago
How do you divide scientific notation problems like this: 0.00053 ÷ 29?
Shtirlitz [24]
You got to remember
\frac{x^m}{x^n}=x^{m+n}

first write them in scienfitic notation
0.00053=5.3*10^{-4}
29=2.9*10^1


so
\frac{0.00053}{29}=
\frac{(5.3)(10^{-4})}{(2.9)(10^1)}=
(\frac{5.3}{2.9})(\frac{10^{-4}}{10^1}=
(1.8275862068965517241379310344828)(10^{-4-1})=
(1.8275862068965517241379310344828)(10^{-5})=
1.8275862068965517241379310344828*10^{-5}

that's the answer
5 0
4 years ago
Trong mặt phẳng tọa độ, viết chương trình đường tròn (C') là ảnh của (C): x^2 +y^2 -2x+4y=0
ryzh [129]

Step-by-step explanation:

Find the properties of the conic section

x

2

+

y

2

−

2

x

+

4

y

x2+y2-2x+4y.0

Center:

(1-2)

Radius:

√5

3 0
3 years ago
Write the absolute value inequality in the form
yawa3891 [41]

Answer:

\large\boxed{|x+7|\geq2}

Step-by-step explanation:

Look at the picture.

|x-a|\geq b\\\\a=\dfrac{-9+(-5)}{2}=\dfrac{-14}{2}=-7\\\\b=-9-(-7)=-9+7=-2\\b=-5-(-7)=-5+7=2\\\\|x-(-7)|\geq2\\\\|x+7|\geq2\\\\Check:\\\\|x+7|\geq2\iff x+7\geq2\ \vee\ x+7\leq-2\qquad\text{subtract 7 from both sides}\\\\x+7-7\geq2-7\ \vee\ x+7-7\leq-2-7\\\\x\geq-5\ \vee\ x\leq-9\qquad CORRECT\ :)

4 0
4 years ago
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