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kobusy [5.1K]
3 years ago
9

On what interval(s) is the graph decreasing? - use interval notation

Mathematics
1 answer:
Anna [14]3 years ago
6 0
The function is decreasing from -6 to -3, that is, on the interval (-6,-3), and again on the interval (1, infinity).  

The function is increasing on (-3,1).

No local or absolute minimum.

(1,4) is an absolute max.
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Which expression is a possible leading term for the polynomial function graphed below?
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Answer:

D, 22x^9

Step-by-step explanation:

Here's a key for end behavior: Look at the leading term

x^even = x -> neg inf, f(x) -> pos inf; x -> pos inf, f(x) -> pos inf

-x^even = x -> neg inf, f(x) -> neg inf; x -> pos inf, f(x) -> neg inf

x^odd = x -> neg inf, f(x) -> neg inf; x -> pos inf, f(x) -> pos inf

-x^odd = x -> neg inf, f(x) -> pos inf; x -> pos inf, f(x) -> neg inf

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2 years ago
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Step-by-step explanation:

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3 0
2 years ago
SLOPES PLSSS HELLLLP<br> what goes in the box?
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6 0
2 years ago
Cos s=-2/5 and sin t=4/5, s and t are in quadrant II<br> find cos(s+t) and cos(s-t)
mojhsa [17]

Answer:

•cos(s+t) = cos(s)cos(t) - sin(s)sin(t) = (-⅖).(-⅗) - (√21 /5).(⅘) = +6/25 - 4√21 /25 = (6-4√21)/25

•cos(s-t) = cos(s)cos(t) + sin(s)sin(t) = (-⅖).(-⅗) + (√21 /5).(⅘) = +6/25 + 4√21 /25 = (6+4√21)/25

cos(t) = ±√(1 - sin²(t)) → -√(1 - sin²(t)) = -√(1 - (⅘)²) = -⅗

sin(s) = ±√(1 - cos²(s)) → +√(1- cos²(s)) = +√(1 - (-⅖)²) = √21 /5

5 0
2 years ago
You want to calculate the displacement of an object thrown over a bridge. Using -10 m/s^2 for acceleration due to gravity, what
MrRissso [65]

<u>Answer</u>

<em>The total displacement of the object is 320 m</em>

<u>Solution-</u>

From the formulas of mechanics,

s=ut+\frac{1}{2}at^{2}

Where,

s = displacement

u = initial velocity = 0               ( ∵ As the body was in rest in the beginning )

t = time taken = 8 s

a = acceleration = -10 m/s²      ( ∵ -ve is because of the downward motion)

Putting all the values,

s= 0 \times 8 + \frac{1}{2}(-10)8^{2} = -320 \ m ( ∵ -ve displacement means it is in downwards)

5 0
3 years ago
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