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Greeley [361]
3 years ago
9

(Cosx)/(1+sinx) - (1+sinx)/(cos) solve

Mathematics
2 answers:
Rina8888 [55]3 years ago
8 0
2/cos x 

........................


vazorg [7]3 years ago
6 0
Cos^2x  - (1+sinx)^2 / cosx(1+sinx)

= cos^2x - (1 + sin^2x + 2sinx) / cosx(1+sinx)

= cos^2x -1 - sin^2x - 2 sinx / cosx(1+sinx)

= - sin^2x - sin^2x - 2 sinx/ cosx(1+sinx)

= -2sin^2x - 2sinx/ cosx (1+sinx)

= -2sinx(sinx+1)/cosx(1+sinx) =  2sinx/cosx = 2 tanx

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<u>Given functions</u>:

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\begin{aligned}A(p) & = \pi p^2\\\\ \implies A[p(t)] & = \pi [p(t)]^2\\& = \pi (6t)^2\\& = \pi 6^2 t^2\\& = 36\pi t^2\end{aligned}

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\begin{aligned}A[p(8)] & = 36\pi t^2\\& = 36 \cdot 3.14 \cdot 8^2\\& = 36 \cdot 3.14 \cdot 64\\& = 113.04 \cdot 64\\& = 7234.56\:\: \sf square\:units\end{aligned}

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