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Sergio [31]
3 years ago
10

Janine wants a necklace 20 beads long. She needs ..... red beads and ..... blue beads.

Mathematics
2 answers:
katrin2010 [14]3 years ago
8 0
The possibilities are: 1 red 19 blue 2 red 18 blue 3 red 17 blue 4 red 16 blue 5 red 15 blue 6 red 14 blue 7 red 13 blue 8 red 12 blus 9 red 11 blue 10 red 10 blue 11 red 9 blue 12 red 8 blue 13 red 7 blue 14 red 6 blue 15 red 5 blue 16 red 4 ⎌blue 17 red 3 blu 18 red 2 blue 19 red 1 blue We haven't got enough information to see which it is. We would need a fraction or a ratio to figure this out.
Tcecarenko [31]3 years ago
4 0

10 red beads

10 blue beads

10 + 10 = 20

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Except as otherwise noted, all CK-12 Content (including CK-12 Curriculum Material) is made available to Users in accordance with the Creative Commons Attribution-Non-Commercial 3.0 Unported (CC BY-NC 3.0) License (http://creativecommons.org/ licenses/by-nc/3.0/), as amended and updated by Creative Com- mons from time to time (the “CC License”), which is incorporated herein by this reference.

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