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kaheart [24]
3 years ago
7

Pls help will give brainlist

Mathematics
1 answer:
gulaghasi [49]3 years ago
7 0
What’s the question...
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A coyote had 10 pups in her third litter. It was twice as many as in her second litter, her second litter, and her second litter
Yuki888 [10]
A coyote had 10 pups in her third litter. (10)
It was twice as many as in her second litter,( 2( second litter) = third litter

her second litter had 3 more pups than her first.( first litter +3)=2nd litter

Find the number of pups in her litter

6 0
3 years ago
What is the surface area?<br> 8 mm<br> 10 mm<br> 5 mm<br> Explain how you arrived at your answer.
lesya692 [45]

Answer:

400 mm

Step-by-step explanation:

8 * 10 = 80

80 * 5 = 400

400 mm

7 0
2 years ago
Read 2 more answers
What is the value of x?
AlekseyPX

Answer:

x = 9 cm

create proportional equation:

\sf \dfrac{9}{3x-20}  = \dfrac{72+9}{3x-20+56}

\sf \dfrac{9}{3x-20}  = \dfrac{81}{3x+36}

\sf 9(3x+36) = 81(3x-20)

\sf 27x+324 = 243x-1620

\sf 27x-243x=-1620-324

\sf  -216x=-1944

\sf x = 9

4 0
2 years ago
Read 2 more answers
The two toy store owners agree to specialize and to trade 30 puzzles for 10 puppets. The terms of trade are still 3 puzzles for
likoan [24]

Based on the exchange rate, at the end of the trade, Lewis will have 31 puppets and 2 puzzles left over while Geppeto will have 158 puzzles and 4 puppets left over.

<h3>What is the exchange rate of puzzles for puppets?</h3>

The exchange rate of puzzles for puppets is 3 to 1.

Geppeto has 20 puppets to exchange for puzzles.

Lewis has 50 puzzles to exchange for puppets.

Number of times Lewis can exchange puzzles for puppets = 50/3 = 16 times.

Lewis will get 16 puppets in exchange for 48 puzzles.

Therefore;

Lewis will have 16 + 25 puppets = 31 puppets and 2 puzzles left over

Geppeto will have 48 + 100 puzzles = 158 puzzles and 4 puppets left over.

in conclusion, the exchange rate determines the how many puzzles and puppets will each one have after they complete their trade.

Learn more about exchange rate at: brainly.com/question/2202418

#SPJ1

7 0
2 years ago
Two persons are to run a race, but one can run 10 meters per second, whereas the other can run 4 meters per second. If the slowe
Kazeer [188]

Answer:12.5 seconds

Step-by-step explanation:hconsidering Runner 1 with a speed of 10m/s

and Runner 2 with a speed of 4 m/s

the equation of displacement for a uniform movement is

x=V*t

so x1=V1*t

and x2=V2*t

and the problem condition is x2=x1+75m

so we proceed to solve the equations.

from equation 2 t=x2/V2

substituting in equation 1 we have

x1=V1(x2/V2) and then the 3 equation

x1=V1((x1+75m)/v2

finally x1=75*(V1/(V2-V1)) =75*(10/(10-4))=125m

then t=(x1/v1)=125/10=12.5 seconds

8 0
3 years ago
Read 2 more answers
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