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vovikov84 [41]
3 years ago
5

Describe each of the following transformation that maps the figures described below. Be specific by naming lines of reflection,

centers of rotation and degrees of rotation, distance and direction of translations, and centers of dilation with a scale factor. Determine if the transformation is a rigid transformation or a similarity transformation. Explain all reasoning.
Part A: Figure 1 →Figure 4
Part B: Figure 2 → Figure 5

Mathematics
1 answer:
Flura [38]3 years ago
8 0

Answer:

Part A: Figure 1 → Figure 4

Rigid Transformation

Equivalent to a reflection about the origin, or a rotation of 180° clockwise or anticlockwise about the origin which are types of rigid transformation

Part B: Figure 2 → Figure 5

Similarity transformation

Figure 5 is Figure 2 dilated by a scale factor of 1/2, which is a form of a similarity transformation

Step-by-step explanation:

Part A: Figure 1 → Figure 4

The coordinates of the vertices of the preimage are;

(5, 10), (2, 4), (9, 2)

The coordinates of the vertices of the image are;

(-9, -2), (-2, -4), (-5, -10)

Which is equivalent to a reflection about the origin, or a rotation of 180° clockwise or anticlockwise about the origin

Part B: Figure 2 → Figure 5

The coordinate points of figure 2 are;

(-9, 2), (-5, 10), and (-2, 4)

The coordinate points of figure 5 are;

(1, 2), (2.5, -1), and (4.5, 3)

The lengths of the sides of figure 2 are;

√((10 - 2)² + ((-5) - (-9))²) = 4·√5

√((10 - 4)² + ((-5) - (-2))²) = 3·√5

√((2 - 4)² + ((-9) - (-2))²) = √53

The lengths of the sides of figure 5 are;

√(((-1) - 2)² + (2.5 - 1)²) = (3·√5)/2

√((4.5 - 2.5)² + (3 - (-1))²) = 2·√5

√((4.5 - 1)² + (3 - 2)²) = (√53)/2

Therefore. Figure 5 is Figure 2 dilated by a scale factor of 1/2

Therefore, given that the sides of Figure 2 and Figure 5 are rotated by 180°

We have;

Figure 5 is obtained as follows;

1) The rotation of figure 2 by 180°, clockwise or anticlockwise about the origin to get;

(-9, 2), (-5, 10), and (-2, 4) → (9, -2), (5, -10), and (2, -4)

2) The image is translated left by 1 blocks and up by 6 blocks as follows;

(9, -2), (5, -10), and (2, -4)  → (8, 4), (4, -4), and (1, 2)

3) The image is then dilated by a scale factor of 1/2  with a center of dilation of (1, 2) to get;

Preimage (8, 4), (4, -4), and (1, 2) → Image (1, 2), (2.5, -1), and (4.5, 3).

You might be interested in
Estimate the difference 625-248
Gekata [30.6K]
Round the numbers to the nearest whole tens


625 close to 630

248 is close to 250

630-250= 380

The estimated difference is 380.

Hope this helps!





3 0
3 years ago
For the length given below draw a line segment to match. Express the measurement as a equivalent mixed number. 4.8 cm
OLEGan [10]

Answer:

there's nothing there

Step-by-step explanation:

5 0
3 years ago
Consider the following argument. If there are as many rational numbers as there are irrational numbers, then the set of all irra
FrozenT [24]

Answer:

b. form: p → q invalid, converse error q ∴ p

Step-by-step explanation:

Let

p = "there are as many rational numbers as there are irrational numbers,"

let

q = "the set of all irrational numbers is infinite."

We can write the above argument as:

If there are as many rational numbers as there are irrational numbers, then the set of all irrational numbers is infinite

p → q

The set of all irrational numbers is infinite

q

There are as many rational numbers as there are irrational numbers

p

So collectively it can be written as:

p → q

 q

∴p

So it looks like

if p then q

q

therefore p

This is a fallacious argument.  This means the conclusion can be false even when the premises are true. This type of argument is invalid.

Suppose we know that “If there are as many rational numbers as there are irrational numbers, then the set of all irrational numbers is infinite” is a true conditional statement. We also know that "the set of all irrational numbers is infinite" is true. This is not enough to say that "there are as many rational numbers as there are irrational numbers," is true. The reason for this is that there is nothing logically about “If p then q” and “q” that means p must follow. So this is a converse error and since converse error is an invalid method of inference rule so this argument is invalid.

Let us prove this argument is invalid with a truth table:

p   q   p → q   q   p

T   T      T       T   T

T   F      F       F   T

F   T      T       T   F

F   F      T       F   F

Since we know that the premises are:

p → q   and  q

and the conclusion is p

and an argument is valid if and only if all of its premises are true, then the conclusion is true. We should check that whenever both p → q   and  q are true then p is true but the third row fails. Thus this is an invalid argument.

6 0
3 years ago
Base your answer to the following question on the diagram shown and the given information
erik [133]

Answer:

  29°

Step-by-step explanation:

  ∠1 ≅ ∠8

  3x+25 = 4x -17

  42 = x . . . . . . . . . . add 17-3x

Now, we can find the measure of ∠1:

  m∠1 = 3(42) +25 = 151

Angle 2 is the supplement to this, so has measure ...

  m∠2 = 180° -151° = 29°

6 0
3 years ago
The length of a rectangular house is two and a half times its width. Solve the problem using x to denote the shorter side of the
denpristay [2]

a.  The construct the expression for the area of the rectangle in terms of x is y=2.5x

b. The area should be 2,560.

Given that,

  • the length of a rectangular house is two and a half times its width.

Based on the above information, the calculation is as follows:

a) The expression should be y = 2.5x

b) The area should be

=2.5x^2\\\\= 2.5(32)^2  

= 2560

Learn more: brainly.com/question/1301963?referrer=searchResults

3 0
2 years ago
Read 2 more answers
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