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scoray [572]
3 years ago
6

Can someone please help me with these 2 problems?

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
7 0

Answer:

Step-by-step explanation:

hope this helped<3

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. When the last 3 digits of a year (such as
Nataliya [291]

Answer:

A ; 23rd century

Step-by-step explanation:

Here, we want to select which of the options is next to have a descending year.

Since all are in the same century i.e 20-something, we do not have an issue with the first digit.

What we need to work on is the last three digits;

We can have 2210, we can have 2321, we can have 2432, we can also have 2543 and so on.

The most recent of all these is the year 2210, so what century does this belong?

Kindly note that, the years 2001-2100 belong to the 21st century.

The years 2101-2200 belong to the 22nd century while the years 2201-2300 belong to the 23rd century

The year we are looking to place is the year 2201 and thus belongs to between 2201-2300 which is the 23rd century

8 0
3 years ago
Just need help with number 2 I will GUVE brainliest
FinnZ [79.3K]
The answer is a and d
7 0
2 years ago
What is initial value for v(t)= 32000(0.90)^t and the value after 13 yrs
marusya05 [52]
He initial value is 32,000 and the value after 13 yrs is 8133.97
5 0
3 years ago
5.4p+13.1=−2.6p+3.5 <br> p=?
mote1985 [20]

Answer:

P= - 16/11 or P= - 1 5/11 or P= - 1.45455

Step-by-step explanation:

Just trust my answer

7 0
2 years ago
An engineer is designing a large steel pad to be installed on the deck of an aircraft carrier. Its total volume will be 18 yd^3.
Shtirlitz [24]

Answer:

The cost of the material for the full-sized pad is;

d) 222,750.00

Step-by-step explanation:

The parameters of the steel pad and the scale model are;

The volume of the deck = 18 yd³

The dimensions of the model of the same material = 6 feet by 4.5 feet and 4.5 inches thick

The weight of the sample, m₂ = 75 lbs

The cost of the steel, P = $55/lb

The dimensions of the sample in yards are;

6 feet = 2 yards, 4.5 feet = 1.5 yards, and 4 inches = 0.\overline 1 yards

The volume of the sample, V₂ = 2 yd. × 1.5 yd. × 0.\overline 1 yd. =  (1/3) yd.³

The density of the sample material, ρ = m₂/V₂

∴ The density of the sample material, ρ = 75 lbs/((1/3)yd.³) = 225 lbs/yd³

Therefore, the density of the material of the pad, ρ = 225 lbs/yd³

The mass of the steel  pad, m₁ = ρ × V₁

∴ The mass of the steel  pad, m₁ = 225 lbs/yd³ × 18 yd³ = 4,050 lbs

The cost of the material for the full-sized steel pad, C = m₁ × P

∴ C = 4,050 lbs × $55/lb = $222,750

6 0
3 years ago
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