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garik1379 [7]
2 years ago
8

A car travels 81 miles in 3 hours. If it continues traveling at the same rate, how many miles would it travel in 5 hours?

Mathematics
1 answer:
wel2 years ago
8 0
The car would travel 135 miles bc you multiply 81×5 and get 405 ,then divide that answer by 3
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There are two numbers, one is 7 more than twice the other. The sum of the numbers is 43. Make the equation to find the smaller n
Mrrafil [7]

Answer:

Smaller number: 12

Greater number: 31

Step-by-step explanation:

Hi there!

Let x equal to the smaller number.

Let y be equal to the greater number.

<u>1) Translate the information into equations</u>

"One is 7 more than twice the other"

⇒ y=2x+7

"The sum of the numbers is 43"

⇒ x+y=43

<u>2) Use substitution to solve for the smaller number</u>

x+y=43

Plug the equation y=2x+7 into the above equation

x+(2x+7)=43\\x+2x+7=43\\3x+7=43

Subtract both sides by 7

3x+7-7=43-7\\3x=36

Divide both sides by 3 to isolate x

\frac{3x}{3} = \frac{36}{3} \\x=12

Therefore, the smaller number equates to 12.

<u>3) Use substitution to solve for the greater number</u>

x+y=43

Plug in x as 12

12+y=43

Subtract both sides by 12 to isolate y

12+y-12=43-12\\y=31

Therefore, the greater number equates to 31.

I hope this helps!

3 0
3 years ago
A car covers a distance of 450 m in 1 minute whereas a train covers
velikii [3]
Speed = distance/ time
Car : 450m/1min
Train: 69km/45 min
7 0
3 years ago
The manufacturing of semiconductor chips produces 2% defective chips. Assume that the chips are independent and that a lot conta
Dmitriy789 [7]

Answer:

a) The approximate probability that more than 25 chips are defective is 0.1075.

b)  The approximate probability of having between 20 and 30 defecitve chips is 0.44.

Step-by-step explanation:

Lets call X the total amount of defective chips. X has Binomial distribution with  parameters n=1000, p =0.02. Using the Central Limit Theorem, we can compute approximate probabilities for X using a normal variable with equal mean and standard deviation.

The mean of X is np = 1000*0.2 = 20, and the standard deviation is √np(1-p) = √(20*0.98) = 4.427

We will work with a random variable Y with parameters μ=20, σ=4.427. We will take the standarization of Y, W, given by

W = \frac{Y-\mu}{\sigma} = \frac{Y-20}{4.427}

The values of the cummmulative distribution function of the standard normal random variable W, which we will denote \phi , can be found in the attached file. Now we can compute both probabilities. In order to avoid trouble with integer values, we will correct Y from continuity.

a)

P(X > 25) = P(X > 25.5)  \approx P(Y>25.5) = P(\frac{Y-20}{4.427} > \frac{25.5-20}{4.427}) =\\P(W > 1.2423) = 1-\phi(1.2423) = 1-0.8925 = 0.1075

Hence the approximate probability that more than 25 chips are defective is 0.1075.

b)

P(20

As a result, the approximate probability of having between 20 and 30 defecitve chips is 0.44.

Download pdf
4 0
3 years ago
What is the area of the trapezoid?
ivolga24 [154]

the answer is B. 72 mm^2 because

9x4.5=40.5

then

7x4.5=31.5

then

40.5+31.5=72.0 mm^2

7 0
3 years ago
1) Simplify 16x – 7y - 19x - 4y​
Vesnalui [34]

Answer:

-3x-11y is the answer.

3 0
3 years ago
Read 2 more answers
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