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Elis [28]
2 years ago
9

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Mathematics
2 answers:
UNO [17]2 years ago
8 0

Answer:

V= 8.5(5.5)(13)

V = 607.75 cubic inches

Step-by-step explanation:

Volume of a right rectangular prism is V=lwh where l is length, w is width, and h is height.

Mashcka [7]2 years ago
7 0

Answer:

607.75 cm3

Step-by-step explanation:

v = L*w*h

8.5 * 5.5 * 13 = 607.75

607.75 cm3

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The stock's value dropped from $38.50 to $34.00.What negative number shows the change in value?
schepotkina [342]
$-4.50 change in value
5 0
3 years ago
You have a wooden rod which is 24 1/2 inches long. Carlos needs a piece which is 8 3/4 inches long and Amanda needs a piece whic
ipn [44]

Answer:

8 3/4 inches

Step-by-step explanation:

Total length of the rod = 24 1/2 inches

Carlos = 8 3/4 inches

Amanda = 6 3/8 inches

length of the rod remaining = Total length - ( Carlos + Amanda)

= 24 1/2 - (8 3/4 + 6 3/8)

= 49/2 - (35/4 + 51/8)

= 49/2 - ( 75+51/8)

= 49/2 - 126/8

= 196-126/8

= 70/8

= 8 6/8 inches

= 8 3/4 inches

Length of rod remaining = 8 3/4 inches

6 0
4 years ago
Help asap pls!!!! i need the questions answered also !!
Vikki [24]

Answer:

it wold be A

Step-by-step explanation:

5 0
3 years ago
A 10 metre length of Wood is marked out into 10 equal lengths. How many metres from one end is the third mark?
Eduardwww [97]

3 metres from one end to the third mark

Solution:

Total length of wood = 10 metre

Wood is marked into 10 equal length.

$\text{Length of each marking}=\frac{\text{Total length}}{\text{Number of marking}}

                                     $=\frac{10}{10}

                                     = 1 metre

Length of each marking = 1 metre

Number of metres from one end to third mark = 1 + 1 + 1 = 3 metre

The image of the marking is attached below.

Hence 3 metres from one end to the third mark.

7 0
3 years ago
Which of the following is a solution to the inequality below?<br> 5 &gt; v
ArbitrLikvidat [17]

Answer:

v = 4

Step-by-step explanation:

4 is less than 5. 7,8 and 10 are all greater than 5.

8 0
4 years ago
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