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3 years ago

7

two friends bought a $14 pizza. Each person bought their own drink. The total cost of the food can be represented by the express

ion $2x + $14. What expression represents the cost of food for one person

1 answer:

yanalaym [24]3 years ago

4 0

The expression might be x=7

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- 22 - 7v = - 3(8V + 4)<br> Round to the nearest hundreth

Dmitriy789 [7]

Answer:

v = 0.58

Step-by-step explanation:

-22 - 7v = -3(8v + 4)

Expand -3(8v + 4)

3 * 8v - 3 * 4

Simplify -3 * 8v -3 * 4

= -24v - 12

-22 - 7v = -24v - 12

Add 22 to both sides

-7v = -24v +10

Add 24v to both sides

17v = 10

$\frac{17v}{17} =\frac{10}{17}$

$v =\frac{10}{17}$

$v=0.58$

5 0

3 years ago

Can someone help me please ?

denis-greek [22]

It is the one second from the top. the line is straight (y=-3) until it hits x=-1 then it starts increasing significantly

8 0

3 years ago

Express each rate as a unit rate. 720 miles traveled on 60 gallons of gasoline=

Brut [27]

720 miles traveled on 60 gallons of gasoline.
Express this on its Unit Rate.
To get the answer, we need to divide 720 miles by 60 gallons of gasoline
=> 720 / 60 = 12 miles /gallons
Thus, in every 1 gallon of gasoline, you can travel 12 miles.
So, the expression would be like this:
720 miles / 60 gallons = 12 miles / gallon
Let’s check our answer
=> 12 miles x 60 gallons = 720 miles.
Thus, we got the correct answer.

7 0

3 years ago

A simple random sample of 50 items from a population with 7 resulted in a sample mean of 35.

Vilka [71]

The 90% , 99% confidence interval for the population mean is 32.145 < $\rm \mu$ < 35.855 and 31.093 < $\rm \mu$ < 36.907

<h3>What is Probability ?</h3>

Probability is the study of likeliness of an event to happen.

It is given that

Total Population = 50

Mean = 35

The confidence interval is given by

$\rm CI = \mu + z \dfrac{s}{\sqrt n}$

$\rm \mu$ is the mean

z is the confidence level value

s is the standard deviation

n is the population width

(a) The 90% confidence interval for the population mean

90% $\rm \alpha / 2$ = 0.05

Z = 1.64

34 $\rm \pm$ 1.64 * 8 / √50

34 $\rm \pm$ 1.855

32.145 < $\rm \mu$ < 35.855

(b) The 99% confidence interval for the population mean

99% $\rm \alpha / 2$ = 0.005

Z=2.57

34 $\rm \pm$ 2.57 * 8 / √50

34 $\rm \pm$ 2.907

31.093 < $\rm \mu$ < 36.907

Therefore the confidence interval for population mean has been determined.

The complete question is

A simple random sample of 50 items from a population width =7 resulted in a sample mean of 35. If required, round your answers to two decimal places.

a. Provide a 90% confidence interval for the population mean

b. Provide a 99% confidence interval for the population mean

To know more about Probability

brainly.com/question/11234923

#SPJ1

8 0

2 years ago

Two types of defects are observed in the production of integrated circuit boards. It is estimated that 6% of the boards have sol

aalyn [17]

Answer:

(a) 0.09

(b) 0.06

(c) 0.0018

(d) 0.9118

(e) 0.03

Step-by-step explanation:

Let <em>A</em> = boards have solder defects and <em>B</em> = boards have surface defects.

The proportion of boards having solder defects is, P (A) = 0.06.

The proportion of boards having surface-finish defects is, P (B) = 0.03.

It is provided that the events A and B are independent, i.e.

$P(A\cap B)=P(A)\times P(B)$

(a)

Compute the probability that either a solder defect or a surface-finish defect or both are found as follows:

= P (A or B) + P (A and B)

$=P(A)+P(B)-P(A\cap B)+P(A\cap B)\\=P(A)+P(B)\\=0.06+0.03\\=0.09$

Thus, the probability that either a solder defect or a surface-finish defect or both are found is 0.09.

(b)

The probability that a solder defect is found is 0.06.

(c)

The probability that both defect are found is:

$P(A\cap B)=P(A)\times P(B)\\=0.06\times0.03\\=0.0018$

Thus, the probability that both defect are found is 0.0018.

(d)

The probability that none of the defect is found is:

$P(A^{c}\cup B^{c})=1-P(A\cup B)\\=1-P(A)-P(B)+P(A\cap B)\\=1-P(A)-P(B)+[P(A)\times P(B)]\\=1-0.06-0.03+(0.06\times0.03)\\=0.9118$

Thus, the probability that none of the defect is found is 0.9118.

(e)

The probability that the defect found is a surface finish is 0.03.

6 0

4 years ago