How do i estimate quotients 933 divided by 3

1 answer:

8 0

K, so
remember that $\frac{a+b+c}{d} = \frac{a}{d}+ \frac{b}{d}+ \frac{c}{d}$
so
$\frac{933}{3}=\frac{900+30+3}{3} = \frac{900}{3}+ \frac{30}{3}+ \frac{3}{3} = 300+10+1=311$

You might be interested in

Triangle ABC is the pre-image and Triangle ADE is the image. What transformation took place?

adelina 88 [10]

Answer:

translation...........

5 0

3 years ago

Read 2 more answers

The weight of a cat is normally distributed with a mean of 9 pounds and a standard deviation of 2 pounds. Using the empirical ru

coldgirl [10]

If the value of the z-score is 1. Then the probability that a cat will weigh less than 11 pounds will be 0.84134.

<h3>What is the z-score?</h3>

The z-score is a statistical evaluation of a value's correlation to the mean of a collection of values, expressed in terms of standard deviation.

The z-score is given as

z = (x - μ) / σ

Where μ is the mean, σ is the standard deviation, and x is the sample.

The weight of a cat is normally distributed with a mean of 9 pounds and a standard deviation of 2 pounds.

Then the probability that a cat will weigh less than 11 pounds will be

The value of z-score will be

z = (11 – 9) / 2

z = 1

Then the probability will be

P(x < 11) = P(z < 1)

P(x < 11) = 0.84134

Thus, the probability that a cat will weigh less than 11 pounds will be 0.84134.