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Effectus [21]
3 years ago
8

30.54

Mathematics
1 answer:
leonid [27]3 years ago
5 0
<h3>Answer: Choice 2)  sin(B) = cos(90-B)</h3>

Explanation:

The rule is that

sin(A) = cos(B)

if and only if A+B = 90.

Solving for A gets A = 90-B

So we end up with

sin(90-B) = cos(B)

which is the same as

cos(B) = sin(90-B)

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The factory made 950 mousetraps
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The equation y=mx+b is the slope-intercept form of the equation of a line. What is the equation solved for b?
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Step-by-step explanation:


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3 years ago
Read 2 more answers
A lake polluted by bacteria is treated with an antibacterial chemical. Aftertdays, thenumber N of bacteria per milliliter of wat
jeyben [28]

Answer:

N(1)=50 is a minimum

N(15)=4391.7 is a maximum

Step-by-step explanation:

<u>Extrema values of functions </u>

If the first and second derivative of a function f exists, then f'(a)=0 will produce values for a called critical points. If a is a critical point and f''(a) is negative, then x=a is a local maximum, if f''(a) is positive, then x=a is a local minimum.  

We are given a function (corrected)

N(t) = 20(t^2-lnt^2)+ 30

N(t) = 20(t^2-2lnt)+ 30

(a)

First, we take its derivative

N'(t) = 20(2t-\frac{2}{t})

Solve N'(t)=0

20(2t-\frac{2}{t})=0

Simplifying

2t^2-2=0

Solving for t

t=1\ ,t=-1

Only t=1 belongs to the valid interval 1\leqslant t\leqslant 15

Taking the second derivative

N''(t) = 20(2+\frac{2}{t^2})

Which is always positive, so t=1 is a minimum

(b)

N(1)=20(1^2-2ln1)+ 30

N(1)=50 is a minimum

(c) Since no local maximum can be found, we test for the endpoints. t=1 was already determined as a minimum, we take t=15

(d)

N(15)=20(15^2-2ln15)+ 30

N(15)=4391.7 is a maximum

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3 years ago
What is the volume rounded to the nearest tenth of the largest sphere that can fit inside of the box ?
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Answer:

36 cubic units.........................

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2 years ago
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