All categories

3 years ago

Round this number to nearest 100 5,382,619

Mathematics

2 answers:

baherus [9]3 years ago

7 0

5,382,600 is your answer.

Inessa [10]3 years ago

3 0

619, 5 or above give it a shove, 4 or below leave it alone

You might be interested in

Please help me

Whitepunk [10]

First solve your inequality step by step.

y+15<3

= y<-12

Answer is A. y<-12

Answer will help you.

Brainliest answer and Verified answers.

4 0

3 years ago

Please help me ASAP!!!

OLga [1]

Answer: The answer would be B

Step-by-step explanation:

The reason for this is because the triangles are similar they are also congruent. df=bc, fe=ac, ed=ab.

Because de=ba and ba=4 in. that would mean that de would also be 4in.

3 0

4 years ago

36% of 112= what because I’m so confused

Gennadij [26K]

Answer:

40.32

Step-by-step explanation:

112 ÷ 100 = 1.12

1.12 × 36 = 4.032

6 0

3 years ago

The scale on a map is 0.25 inches : 1¾ miles. If two cities are 1.8 inches apart on the map, what is the real life distance betw

slava [35]

Answer:

12.6 miles I think. I would wait for another answer to be possitive.

8 0

3 years ago

The curve y = |x|/ 5 − x2 is called a bullet-nose curve. find an equation of the tangent line to this curve at the point (2, 2).

diamong [38]

We have the following curve:

$y=\frac{\left | x \right |}{5-x^2}$

So we need to find an equation of the tangent line to this curve at the point $(2,2)$ . So let's find out if this point, in fact, belongs to the curve:

 $If \ x=2 \\ \\ y=\frac{\left | 2 \right |}{5-2^2}=\frac{\left | 2 \right |}{5-4}=2$ .

We also know that:

 $\left | x \right |= \left \{ {{x \ if \ x \ \geq 0} \atop {-x \ if \ x\ \textless \ 0}} \right.$ 

Given that the point is:

 $(2,2)\ that \ is: \\ x=2\ \textgreater \ 0$

Then we will say that:

$\left | x \right |=x$

Therefore:

$y=\frac{x}{5-x^2}$

Computing the derivative:

$y=\frac{x}{5-x^2} \\ \frac{dy}{dx}= \frac{(1)(5-x^2)-(-2x)x}{(5-x^2)^2}=\frac{5+x^2}{(5-x^2)^2}$

So the derivative solved for $x=2$ is in fact the slope of the line at the point $(2,2)$ , then:

$\frac{dy}{dx} |_{x=2}=\frac{5+x^2}{(5-x^2)^2}|_{x=2}=\frac{5+2^2}{(5-2^2)^2}=9 \\ \\ \therefore m=\frac{dy}{dx} |_{x=2}=9$

Finally, the tangent line is:

$y-y_1=m(x-x_1) \\ \therefore y-2=9(x-2) \\ \therefore \boxed{y=9x-16}$

This is shown in the figure below.

8 0

3 years ago