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mina [271]
3 years ago
9

Round this number to nearest 100 5,382,619

Mathematics
2 answers:
baherus [9]3 years ago
7 0

5,382,600 is your answer.

Inessa [10]3 years ago
3 0
619, 5 or above give it a shove, 4 or below leave it alone
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From least to greatest 0.75, 1/2, 0.4, and 1/5
Lena [83]
1/5, 0.4, 1/2, 0.75

Just convert all of them to decimals first then it should be easy or you . 
3 0
3 years ago
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A beetle was running along a number line, Then the bug ran from 24 to 78. What distance did it cover? If this run took the bug 9
Margaret [11]

Answer:

it covered 54 and ran 6 per 9 second

Step-by-step explanation:

step 1. 78-24 = 54

step 2. 54/9 = 6

3 0
3 years ago
2(vh)/k=r Solve equation for v in terms of all other variables involved
aivan3 [116]

The equation v in terms of other variables is v = kr/2h

<h3>What is the subject of an equation?</h3>

It is a variable which is expressed in terms of other variables involved in the formula.

Formulas are written so that a single variable, the subject of the formula is on the L.H.S. of the equation. Everything else goes on the right side of the equation. We evaluate the formula by substituting for the literal numbers on the right hand side.

2(vh) / k = r

by cross multiplication

2(vh) = kr

divide both sides by 2h

v = kr/2h

In conclusion, v in terms of other variables is  kr/2h

Learn more about subject of an equation: brainly.com/question/657646

#SPJ1

6 0
1 year ago
Question down below
Nitella [24]

Answer:

angle s is 22 degrees

Step-by-step explanation:

hope this helped

8 0
3 years ago
Genius question: A long level railway bridge passes over a railroad track, which is 100 feet below it and at right angles to it.
nataly862011 [7]

Answer: <u>110 feet per second</u>

Step-by-step explanation:

In this problem we will assume that the car at 45 miles per hour is moving into the x direction with a high of 100 feet, and the train is going in the y direction, so they trajectories will made an angle of 90º.

Now we can calculate the speed of the trains in feet per second so:

S1=\frac{45*5280}{3600}=66

S2=\frac{60*5280}{3600}=88

So we can make a right triangle with sides 66 and 88 and the hypotenuse will be the rate that the trains will separate per second so:

h=\sqrt{66^{2} +88^{2} } =\sqrt{4356+7744}

h=\sqrt{12100}=110

Is important to have in mind that the initial high is not going to change how fast the trains will separate, however, if we are going to calculate the distance we should have it in the calculations.

7 0
3 years ago
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